Bash script need to convert string to date
The date
command is quite flexible in recognizing strings that represent dates. So, for example:
$ date -d 'Oct 29 2018'
Mon Oct 29 00:00:00 CET 2018
The -d
flag instructs date
to display the date given to it as a string.
You can add the +FORMAT
parameter to convert the date as you like. For example:
$ date -d 'Oct 29 2018' '+%Y-%m-%d'
2018-10-29
Refer to man date
for the option you have to set the output format.
EDIT:
Sorry, I didn't get your reference to -mtime
. Are you talking about the find
filter? If so, I guess you need the difference between today and your OLDEST_DATE
, in days.
You can obtain it by converting dates to the Epoch format (seconds since 1970-01-01 00:00:00 UTC). For example:
$ current="$(date '+%s')"
$ oldest_date_epoch="$(date -d "$OLDEST_DATE" '+%s')"
$ diff_days=$(( ("$current" - "$oldest_date_epoch") / (3600 * 24) ))
Note this is not a general solution, since date
cannot understand foreign languages.
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stefzeer
Updated on September 18, 2022Comments
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stefzeer over 1 year
Hello I have this bash script for checking the integrity of backups. I need to edit it as I have to make warn me when the oldest backup is more than 60 days (as we delete those).
Now the date is extracted from another file
OLDEST_DATE=`cat /tmp/B_BACKUP_TMP.out | head -1 | cut -f5,6,8 -d" "`
in the following format :
Oct 29 2018
However, this format can't get picked up when I try to use it with -mtime +60
Any ideas how I can convert it ?
Thank you.