Convert String (representing decimal number) to long

Question

I've googled around a bit but could not find examples to find a solution. Here is my problem:

String s = "100.000";
long l = Long.parseLong(s);

The 2nd line of code which tries to parse the string 's' into a long throws a NumberFormatException.

Is there a way around this? the problem is the string representing the decimal number is actually time in milliseconds so I cannot cast it to int because I lose precision.

Solution 1

You could use a BigDecimal to handle the double parsing (without the risk of precision loss that you might get with Double.parseDouble()):

BigDecimal bd = new BigDecimal(s);
long value = bd.longValue();

Solution 2

as i don't know is your 100.000 equals 100 or 100 000 i think safest solution which i can recommend you will be:

NumberFormat nf = NumberFormat.getInstance();
Number number = nf.parse("100.000");
long l = number.longValue();

Solution 3

'long' is an integer type, so the String parse is rejected due to the decimal point. Selecting a more appropriate type may help, such as a double.

Comments

[Uncle Iroh]

stackoverflow.com/questions/888088/…

[Kenogu Labz]

Yeah, I realized a bit late that this may be European notation. I may just delete this answer, as it seems others have covered the gamut of good possible solutions.

[Torque]

This is an extremely bad idea. Doubles are not lossless! Following this advice will likely lead to data corruption.

[Smith]

this would result in wrong number, 100.00 would be 10000