Efficiently calculate word frequency in a string
Solution 1
Use collections.Counter
:
>>> from collections import Counter
>>> test = 'abc def abc def zzz zzz'
>>> Counter(test.split()).most_common()
[('abc', 2), ('zzz', 2), ('def', 2)]
Solution 2
>>>> test = """abc def-ghi jkl abc
abc"""
>>> from collections import Counter
>>> words = Counter()
>>> words.update(test.split()) # Update counter with words
>>> words.most_common() # Print list with most common to least common
[('abc', 3), ('jkl', 1), ('def-ghi', 1)]
Solution 3
You can also use NLTK
(Natural Language ToolKit). It provide very nice libraries for studying the processing the texts.
for this example you can use:
from nltk import FreqDist
text = "aa bb cc aa bb"
fdist1 = FreqDist(text)
# show most 10 frequent word in the text
print fdist1.most_common(10)
the result will be:
[('aa', 2), ('bb', 2), ('cc', 1)]
sazr
Updated on March 25, 2021Comments
-
sazr about 3 years
I am parsing a long string of text and calculating the number of times each word occurs in Python. I have a function that works but I am looking for advice on whether there are ways I can make it more efficient(in terms of speed) and whether there's even python library functions that could do this for me so I'm not reinventing the wheel?
Can you suggest a more efficient way to calculate the most common words that occur in a long string(usually over 1000 words in the string)?
Also whats the best way to sort the dictionary into a list where the 1st element is the most common word, the 2nd element is the 2nd most common word and etc?
test = """abc def-ghi jkl abc abc""" def calculate_word_frequency(s): # Post: return a list of words ordered from the most # frequent to the least frequent words = s.split() freq = {} for word in words: if freq.has_key(word): freq[word] += 1 else: freq[word] = 1 return sort(freq) def sort(d): # Post: sort dictionary d into list of words ordered # from highest freq to lowest freq # eg: For {"the": 3, "a": 9, "abc": 2} should be # sorted into the following list ["a","the","abc"] #I have never used lambda's so I'm not sure this is correct return d.sort(cmp = lambda x,y: cmp(d[x],d[y])) print calculate_word_frequency(test)