Google places Api Key

Question

I have searched through here for other questions related to the same topic and cannot find a definite answer.

My problem seems the same as many others in that I cannot get a response from Google Places Api.

I am trying from within an iphone app, yes the code is correct , I have checked and in desperation just resorted to wiping out the code to just make a request using the examples provided by the Docs on Google Places.

Tried putting the url into a browser, always the same response, whichever browser.

{
     "html_attributions" : [],
     "results"  : [],
     "status"  : "REQUEST DENIED"
}

I have tried making new keys, same result and yes the identifer for the app is also listed.

Is there a time frame before being able to use the key.

Solution 1

Here how I've done this

1)You need to login with your google account

2)Google APi Console will Appear

3)Look out at Screenshot

4)you will find Services over there ,click on it where you can have choose API you would like to use

5)then go to API Access as shown in you can get your Google API Key.

Thanks

Advice -use your own Google API key

Solution 2

You probably need 'sensor' parameter in your request URL, I guess.

Just set 'sensor=false&' in the URL and try it.

Solution 3

In order to use the google place API, you need to do the following steps on https://console.developers.google.com:

You need to go your project.

1: Activate Google places API depending upon your clients: iOS, Android or web.

2: Then go to the Credentials section on the left.

3: Generate a SERVER key.

Insert that key into your google place api call. Example:

https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=-33.8670522,151.1957362&radius=500&types=food&name=cruise&key=SERVERKEY

Its a simple GET Rest call.

Comments

[Arsalan]

This will help you : [link] (stackoverflow.com/questions/14654758/…)

[user2925054]

and change the location it doesn't have any places search results try this ex: 26.175677,%2091.741714 with types = post_office

[VinceFior]

The 'sensor' parameter is no longer required. developers.google.com/places/documentation/search#Sensor

[VinceFior]

Works for me - I didn't realize I had to use a Browser key.

[Vaibhav Limbani]

@VinceFior I'm glad that..that it helps you