How to efficiently check if a list of words is contained in a Spark Dataframe?

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You should consider using pyspark sql module functions instead of writing a UDF, there are several regexp based functions:

First let's start with a more complete sample data frame:

df = sc.parallelize([["a","b","foo is tasty"],["12","34","blah blahhh"],["yeh","0","bar of yums"], 
                     ['haha', '1', 'foobar none'], ['hehe', '2', 'something bar else']])\
    .toDF(["col1","col2","col_with_text"])

If you want to filter lines based on whether they contain one of the words in words_list, you can use rlike:

import pyspark.sql.functions as psf
words_list = ['foo','bar']
df.filter(psf.col('col_with_text').rlike('(^|\s)(' + '|'.join(words_list) + ')(\s|$)')).show()

    +----+----+------------------+
    |col1|col2|     col_with_text|
    +----+----+------------------+
    |   a|   b|      foo is tasty|
    | yeh|   0|       bar of yums|
    |hehe|   2|something bar else|
    +----+----+------------------+

If you want to extract the strings matching the regular expression, you can use regexp_extract:

df.withColumn(
        'extracted_word', 
        psf.regexp_extract('col_with_text', '(?=^|\s)(' + '|'.join(words_list) + ')(?=\s|$)', 0))\
    .show()

    +----+----+------------------+--------------+
    |col1|col2|     col_with_text|extracted_word|
    +----+----+------------------+--------------+
    |   a|   b|      foo is tasty|           foo|
    |  12|  34|       blah blahhh|              |
    | yeh|   0|       bar of yums|           bar|
    |haha|   1|       foobar none|              |
    |hehe|   2|something bar else|              |
    +----+----+------------------+--------------+
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Kishintai
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Kishintai

Updated on July 09, 2022

Comments

  • Kishintai
    Kishintai almost 2 years

    Using PySpark dataframes I'm trying to do the following as efficiently as possible. I have a dataframe with a column which contains text and a list of words I want to filter rows by. So:

    Dataframe would look like this

    df:
    col1    col2   col_with_text
    a       b      foo is tasty
    12      34     blah blahhh
    yeh     0      bar of yums
    

    The list will be list = [foo,bar] And thus result will be:

    result:
    col1    col2   col_with_text
    a       b      foo
    yeh     0      bar
    

    Afterwards not only identical string matching will be done but also tested for similarity by using SequenceMatcher or so. This is what I already tried:

    def check_keywords(x):
       words_list = ['foo','bar']
    
       for word in x
           if word == words_list[0] or word == words_list[1]:
               return x
    
    result = df.map(lambda x: check_keywords(x)).collect()
    

    Unfortunately I was unsuccesfull, could someone help me out? Thanks in advance.

  • Be Chiller Too
    Be Chiller Too over 4 years
    Hi, why are you using lookaheads in your regexps?