HOW to EXIT using "start" in batch files of MSDOS

Question

I want to copy some files into diffent USB disks, and want to use START to open several consoles as follows:

start copy a.txt h:
start copy a.txt i:
start copy a.txt j:

But everytime I run the batch file, there are 3 consoles without exiting. How can I realize this EXIT function WITHOUT using 3 batch files and "call" commands as:

copy.bat:

call a.bat
call b.bat
call c.bat
exit

and three called batch files as:

a.bat:

start copy a.txt h:
exit

b.bat:

start copy a.txt i:
exit

c.bat:

start copy a.txt j:
exit

I already tried this, but it DOES NOT work:

start copy a.txt h: && exit
start copy a.txt i: && exit
start copy a.txt j: && exit

Solution 1

You need to escape && so it becomes part of the command executed by start and not the parent batch file.

start copy a.txt h: ^&^& exit

To close the new console even if there are errors you can do:

start "" "%comspec%" /c copy a.txt h:

Solution 2

You can use start to start a new cmd window and close it once the command has been run like this:

start cmd /c copy a.txt h: