how to ignore duplicate documents when using insertMany in mongodb php library?
Try to replace 'continueOnError' option by 'ordered' set to false, based on the documentation, when ordered option is set to false the insertMany will continue writing, even if a single write fails.
here is the docs link: insertMany
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Behzadsh almost 2 years
I am using mongo php library, and trying to insert some old data into mongodb. I used
insertMany()
method and pass a huge array of document, that may have duplicate documents on unique indexes.Lets say I have a users collection and have these indexes:
[ { "v" : 1, "key" : { "_id" : 1 }, "name" : "_id_", "ns" : "test.users" }, { "v" : 1, "unique" : true, "key" : { "email" : 1 }, "name" : "shop_id_1_title_1", "ns" : "test.users" } ]
If there's a duplicate document,
MongoDB\Driver\Exception\BulkWriteException
would raise and stop the process. I want to find a way to ignore inserting duplicate documents (and also preventing the exception from raise) and continue inserting other documents.I found in php.net documentation a flag called
continueOnError
that do the trick but it seems that it's not working with this library.The example from php.net:
<?php $con = new Mongo; $db = $con->demo; $doc1 = array( '_id' => new MongoId('4cb4ab6d7addf98506010001'), 'id' => 1, 'desc' => "ONE", ); $doc2 = array( '_id' => new MongoId('4cb4ab6d7addf98506010002'), 'id' => 2, 'desc' => "TWO", ); $doc3 = array( '_id' => new MongoId('4cb4ab6d7addf98506010002'), // same _id as above 'id' => 3, 'desc' => "THREE", ); $doc4 = array( '_id' => new MongoId('4cb4ab6d7addf98506010004'), 'id' => 4, 'desc' => "FOUR", ); $c = $db->selectCollection('c'); $c->batchInsert( array($doc1, $doc2, $doc3, $doc4), array('continueOnError' => true) );
And the way I tried to use the flag with mongo php library:
<?php $users = (new MongoDB\Client)->test->users $collection->insertMany([ [ 'username' => 'admin', 'email' => '[email protected]', 'name' => 'Admin User', ], [ 'username' => 'test', 'email' => '[email protected]', 'name' => 'Test User', ], [ 'username' => 'test 2', 'email' => '[email protected]', 'name' => 'Test User 2', ], ], [ 'continueOnError' => true // This option is not working ]);
The code above still raise the exception, and seems not to work. Is there other option flag or is there any way to do this?
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s7vr over 7 yearsCan you be more specific as it what seems to be not working ? You can add an example to help us understand.
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Behzadsh over 7 years@Veeram more details and example added as you requested
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