How to Parse a JSON Object In Android

Question

I am having some problems pulling values from a JSON object. Here is my code

try {
    JSONObject json = new JSONObject(result);
    JSONObject json2 = json.getJSONObject("results");
    test = json2.getString("name");     
} catch (JSONException e) {
    e.printStackTrace();
}

test is declared as a String. When the code runs it is showing null. If I hover over json2 in debug mode I can see all the values and names within the object.

I also tried

test = json2.length();

This returned test = 0. Even when I hover over the json2 object I can read the values within the object.

Here is an example of a JSON string I will use.

{
    "caller":"getPoiById",
    "results":
    {
        "indexForPhone":0,
        "indexForEmail":"NULL",
        "indexForHomePage":"NULL",
        "indexForComment":"NULL",
        "phone":"05137-930 68",
        "cleanPhone":"0513793068",
        "internetAccess":"2",
        "overnightStay":"2",
        "wasteDisposal":"2",
        "toilet":"2",
        "electricity":"2",
        "cran":"2",
        "slipway":"2",
        "camping":"2",
        "freshWater":"2",
        "fieldNamesWithValue":["phone"],
        "fieldNameTranslations": ["Telefon"],
        "id":"1470",
        "name":"Marina Rasche Werft GmbH & Co. KG",
        "latitude":"52.3956107286487",
        "longitude":"9.56583023071289"
    }
}

Solution 1

In the end I solved it by using JSONObject.get rather than JSONObject.getString and then cast test to a String.

private void saveData(String result) {
    try {
        JSONObject json= (JSONObject) new JSONTokener(result).nextValue();
        JSONObject json2 = json.getJSONObject("results");
        test = (String) json2.get("name");
    } catch (JSONException e) {
        e.printStackTrace();
    }
}

Solution 2

In your JSON format, it do not have starting JSON object

Like :

{
    "info" :       <!-- this is starting JSON object -->
        {
        "caller":"getPoiById",
        "results":
        {
            "indexForPhone":0,
            "indexForEmail":"NULL",
            .
            .
         }
    }
}

Above Json starts with info as JSON object. So while executing :

JSONObject json = new JSONObject(result);    // create JSON obj from string
JSONObject json2 = json.getJSONObject("info");    // this will return correct

Now, we can access result field :

JSONObject jsonResult = json2.getJSONObject("results");
test = json2.getString("name"); // returns "Marina Rasche Werft GmbH & Co. KG"

I think this was missing and so the problem was solved while we use JSONTokener like answer of yours.

Your answer is very fine. Just i think i add this information so i answered

Thank you

Solution 3

Take a look at http://developer.android.com/reference/org/json/JSONTokener.html

This might fix your issue.

Solution 4

JSONArray jsonArray = new JSONArray(yourJsonString);

for (int i = 0; i < jsonArray.length(); i++) {
     JSONObject obj1 = jsonArray.getJSONObject(i);
     JSONArray results = patient.getJSONArray("results");
     String indexForPhone =  patientProfile.getJSONObject(0).getString("indexForPhone"));
}

Change to JSONArray, then convert to JSONObject.

View more solutions

Comments

[harism]

JSON string example you provided works for me at least. Are you facing problems with that string too?

[Giant]

can you show the whole code for this?or atleast help me with my problem with jsonobject

[jiduvah]

I posted the updated code above, but I still have the same problem @Dave G

[Raiyan]

I ran into the same problem and solved it by following your approach. Did you look for/manage to find an explanation why this works but getJSONObject doesn't ?

[Daniel Kabu Asare]

because your json is an object and not an array so you use Jsonobject