How to show the requested URL in a JSP error page?
Here is a simple example of JSP error page that shows the error code and the URL of the requested page:
404.jsp:
<%@ page language="java" isErrorPage="true" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<title>Error page</title>
<meta charset="utf-8">
</head>
<body>
<button onclick="history.back()">Back to Previous Page</button>
<h1>404 Page Not Found.</h1>
<br />
<p><b>Error code:</b> ${pageContext.errorData.statusCode}</p>
<p><b>Request URI:</b> ${pageContext.request.scheme}://${header.host}${pageContext.errorData.requestURI}</p>
<br />
</body>
</html>
Useful reading:
- "JSP.1.4 Error Handling" section in the JavaServer Pages Specification (JSR 245).
- Handling JSP Page Errors (from the official Java EE 5 Tutorial)
P.S.
The use of scriptlets inside JSP is highly discouraged. Read this post.
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informatik01
I work as a senior software developer at French-Estonian IT and Telecommunications company Onoff Telecom. My main interests are Java, the related tools and frameworks (especially Spring Framework), and server side development in general. I love Computer Science. I am interested in learning and gaining more knowledge about programming languages, frameworks, platforms, techniques, algorithms and other Computer Science related topics. I find Stack Overflow a fantastic place to learn and find solutions to programming problems.
Updated on September 15, 2022Comments
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informatik01 over 1 year
In the error page I would like to display the URL what the user requested.
In my web.xml:
<?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0"> <display-name>MyStuff</display-name> <error-page> <error-code>404</error-code> <location>/WEB-INF/error-404.jsp</location> </error-page> </web-app>
This will forward to error-404.jsp, and here is the content of that file:
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1" %> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Page Not found</title> </head> <body> <p align="center"> <% out.println("Requested resource: " + request.getRequestURL()+ " not found"); %> </body> </html>
The problem it is therequest.getRequestURL()
need to be changed, but don't know the keyword for what to search.When I start the browser for
http://localhost:8080/MyStuff
then I get the following error:Requested resource: http://localhost:8080/MyStuff/WEB-INF/error-404.jsp not found
How to solve this?