How to undo "set -x" in unix shell?
You can use set +x
to switch it back. The output of help set
describes this:
$ help set
set: set [--abefhkmnptuvxBCHP] [-o option] [arg ...]
...
-v Print shell input lines as they are read.
-x Print commands and their arguments as they are executed.
...
Using + rather than - causes these flags to be turned off. The
flags can also be used upon invocation of the shell. The current
set of flags may be found in $-. The remaining n ARGs are positional
parameters and are assigned, in order, to $1, $2, .. $n. If no
ARGs are given, all shell variables are printed.
Note the “Using +
rather than -
causes these flags to be turned off” part.
Related videos on Youtube
Brian Peterson
My toolbox: Python, Django & Flask, HTML/CSS, JQuery, Backbone, PostgreSQL/MySQL, Nginx, Debian
Updated on June 28, 2022Comments
-
Brian Peterson almost 2 years
In following some random directions on the internet, trying to debug an issue of mine at a shell (I use zsh), I ran
set -x
. Thanks to this I figured out my issue. However, I'm now in an awkward position of not knowing how to turn this debugging off -- I really don't even understand what I did in the first place, you see.I also figured out that I could just do
zsh
and get a new shell. The obviousunset -x
does not work. I would like to know the correct way. Thanks!Update:
Found this unix&linux stack exchange post about what
-x
does. Still don't know how to turn it off.