JSON parsing using Gson for Java
Solution 1
This is simple code to do it, I avoided all checks but this is the main idea.
public String parse(String jsonLine) {
JsonElement jelement = new JsonParser().parse(jsonLine);
JsonObject jobject = jelement.getAsJsonObject();
jobject = jobject.getAsJsonObject("data");
JsonArray jarray = jobject.getAsJsonArray("translations");
jobject = jarray.get(0).getAsJsonObject();
String result = jobject.get("translatedText").getAsString();
return result;
}
To make the use more generic - you will find that Gson's javadocs are pretty clear and helpful.
Solution 2
In my first gson application I avoided using additional classes to catch values mainly because I use json for config matters
despite the lack of information (even gson page), that's what I found and used:
starting from
Map jsonJavaRootObject = new Gson().fromJson("{/*whatever your mega complex object*/}", Map.class)
Each time gson sees a {}, it creates a Map (actually a gson StringMap )
Each time gson sees a '', it creates a String
Each time gson sees a number, it creates a Double
Each time gson sees a [], it creates an ArrayList
You can use this facts (combined) to your advantage
Finally this is the code that makes the thing
Map<String, Object> javaRootMapObject = new Gson().fromJson(jsonLine, Map.class);
System.out.println(
(
(Map)
(
(List)
(
(Map)
(
javaRootMapObject.get("data")
)
).get("translations")
).get(0)
).get("translatedText")
);
Solution 3
Simplest thing usually is to create matching Object hierarchy, like so:
public class Wrapper {
public Data data;
}
static class Data {
public Translation[] translations;
}
static class Translation {
public String translatedText;
}
and then bind using GSON, traverse object hierarchy via fields. Adding getters and setters is pointless for basic data containers.
So something like:
Wrapper value = GSON.fromJSON(jsonString, Wrapper.class);
String text = value.data.translations[0].translatedText;
Solution 4
You can create corresponding java classes for the json objects. The integer, string values can be mapped as is. Json can be parsed like this-
Gson gson = new GsonBuilder().create();
Response r = gson.fromJson(jsonString, Response.class);
Here is an example- http://rowsandcolumns.blogspot.com/2013/02/url-encode-http-get-solr-request-and.html
Solution 5
One way would be created a JsonObject and iterating through the parameters. For example
JsonObject jobj = new Gson().fromJson(jsonString, JsonObject.class);
Then you can extract bean values like:
String fieldValue = jobj.get(fieldName).getAsString();
boolean fieldValue = jobj.get(fieldName).getAsBoolean();
int fieldValue = jobj.get(fieldName).getAsInt();
Hope this helps.
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Comments
-
Martynas over 3 years
I would like to parse data from JSON which is of type
String
. I am using Google Gson.I have:
jsonLine = " { "data": { "translations": [ { "translatedText": "Hello world" } ] } } ";
and my class is:
public class JsonParsing{ public void parse(String jsonLine) { // there I would like to get String "Hello world" } }
-
MByD about 13 yearsJsonObject extends JsonElement, so it is both.
-
Mike Samuel about 13 yearsDon't you need some setters on those helper classes? Nothing can set the
private String translatedText
without violating access control, so there's no wayfromJSON
could set it in JVMs that have not opted-into reflection trampling all over access control. -
kensen john about 13 years@Mike Samuel shoot completely forgot about the Setters
-
Illegal Argument almost 10 yearsthe first line throws cannot instantiate of the type JsonParser on version gson-2.2.4.jar
-
StaxMan about 9 yearsThen your object structure is NOT matching JSON.
-
user1165560 over 8 yearsString result = jobject.get("translatedText").toString(); This results will include the double quotes. String result = jobject.get("translatedText").getAsString(); doesn't include the quotes.
-
tricknology over 7 yearsAl I the only one who thinks Gson overcomplicates things 98% of the time? A simple JSONObject would do, but we all hate try/catch that much?
-
Mason Wang almost 7 yearsI need to use the parser class, however, I am getting the MalformedJsonException, so I have to be able to do SetLeinient with JsonParser. How?
-
Minkyu Kim over 2 years@IllegalArgument It deprecated. No need to instantiate this class, use the static methods instead as
JsonParser.parse(jsonString);