math.Mod in Go returns integer part instead of floating-point remainder
The result is correct. math.Mod returns the remainder, which really is 2 in this case. It's equivalent to the % operator, but for floating point numbers.
metaleap
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Updated on June 22, 2022Comments
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metaleap almost 2 years
Golang's math.Mod(10, 4) returns 2 -- ie. the integer part of division result 2.5 -- but shouldn't it be "the floating point remainder", that is, 0.5?