Matlab filter() with SciPy lfilter()
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Is there a reason you're adding a an extra dimension when creating your array of ones? Is this what you need:
lfilter(np.ones(windowSize) / windowSize, 1, data)
Author by
theta
Updated on August 02, 2022Comments
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theta over 1 year
According to their documentation for Matlab filter() and SciPy lfilter(), it seems like they should be "compatible". However I have a problem, porting larger Matlab code in Python, for which I get
ValueError: object of too small depth for desired array
. As I can't think of how I can present my source without complicating it, I'll use the example provided in Matlab's documentation:data = [1:0.2:4]'; windowSize = 5; filter(ones(1,windowSize)/windowSize,1,data)
which I translate in Python to:
import numpy as np from scipy.signal import lfilter data = np.arange(1, 4.1, 0.2) windowSize = 5 lfilter(np.ones((1, windowSize)) / windowSize, 1, data)
In this case I get:
ValueError: object too deep for desired array
Why do I get these errors?
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theta about 12 yearsThere is no reason, just my ignorance :) I didn't spotted that while translating. Thanks
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Bi Rico about 12 yearsah yes I remember now, in matlab ones(10) returns a 10 by 10, oh those good old matlab days.