Odd-length string error with binascii.unhexlify
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Using the python console:
>>> help(binascii.unhexlify)
unhexlify(...)
a2b_hex(hexstr) -> s; Binary data of hexadecimal representation.
hexstr must contain an even number of hex digits (upper or lower case).
This function is also available as "unhexlify()"
So the error is consistent. What you have to do is padding with '0'
to have an even number:
>>> binascii.unhexlify('0%x' % n)
'\x01'
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SpiderRico
I once had an unicorn who disliked to eat coconuts on sunny weathers.
Updated on July 16, 2022Comments
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SpiderRico almost 2 years
I'm trying to convert back and forth an ASCII string to its binary representation as follows.
s=chr(0)*15 + chr(0x01) bst = bin(int(binascii.hexlify(s), 16)) n = int(bst, 2) binascii.unhexlify('%x' % n)
However, I get the following error at the end which doesn't make much sense to me.
1 binascii.unhexlify('%x' % n)
TypeError: Odd-length string
What's the issue and how can I solve it ?
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PJ_Finnegan over 2 yearsPadding at the beginning or at the end?