Parse French date in python
Solution 1
dateparser
module can parse dates in the question:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import dateparser # $ pip install dateparser
for date_string in [u"Aujourd'hui", "3 juillet", u"4 Août", u"Hier"]:
print(dateparser.parse(date_string).date())
It translates dates to English using a simple yaml config and passes the date strings to dateutil.parser
.
Output
2015-09-09
2015-07-03
2015-08-04
2015-09-08
Solution 2
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import parsedatetime as pdt # $ pip install parsedatetime pyicu
calendar = pdt.Calendar(pdt.Constants(localeID='fr', usePyICU=True))
for date_string in [u"Aujourd'hui", "3 juillet", u"4 Août", u"Hier"]:
dt, success = calendar.parseDT(date_string)
if success:
print(date_string, dt.date())
Output
3 juillet 2015-07-03
4 Août 2015-08-04
Aujourd'hui, Hier are not recognized (parsedatetime 1.4).
The current version on github (future 1.5) supports customizing the day offsets. It can be used to parse Aujourd'hui, Hier:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import parsedatetime as pdt
class pdtLocale_fr(pdt.pdt_locales.pdtLocale_icu):
def __init__(self):
super(pdtLocale_fr, self).__init__(localeID='fr_FR')
self.dayOffsets.update({u"aujourd'hui": 0, u'demain': 1, u'hier': -1})
pdt.pdtLocales['fr_FR'] = pdtLocale_fr
calendar = pdt.Calendar(pdt.Constants(localeID='fr_FR', usePyICU=False))
for date_string in [u"Aujourd'hui", "3 juillet", u"4 Août", u"Hier",
u"au jour de hui", u"aujour-d’hui",
u"au-jour-d’hui", "demain", "hier",
u"today", "tomorrow", "yesterday"]:
dt, rc = calendar.parseDT(date_string)
if rc > 0:
print(date_string, dt.date())
Output
Aujourd'hui 2014-10-11
3 juillet 2015-07-03
4 Août 2015-08-04
Hier 2014-10-10
demain 2014-10-12
hier 2014-10-10
today 2014-10-11
tomorrow 2014-10-12
yesterday 2014-10-10
To install it, run:
$ pip install git+https://github.com/bear/parsedatetime
Solution 3
First check whether you have the correct locale in your repo:
$ locale -a
C
C.UTF-8
de_AT.utf8
de_BE.utf8
de_CH.utf8
de_DE.utf8
de_LI.utf8
de_LU.utf8
en_AG
en_AG.utf8
en_AU.utf8
en_BW.utf8
en_CA.utf8
en_DK.utf8
en_GB.utf8
en_HK.utf8
en_IE.utf8
en_IN
en_IN.utf8
en_NG
en_NG.utf8
en_NZ.utf8
en_PH.utf8
en_SG.utf8
en_US.utf8
en_ZA.utf8
en_ZM
en_ZM.utf8
en_ZW.utf8
POSIX
If not, do:
$ sudo locale-gen fr_FR.UTF-8
Generating locales...
fr_FR.UTF-8... done
Generation complete.
Then go back to python:
$ python
>>> import locale
>>> import datetime
>>> locale.setlocale(locale.LC_ALL, 'fr_FR.UTF-8')
'fr_FR.UTF-8'
>>>
>>> date_txt = "Dimanche 3 Juin 2012"
>>> DATE_FORMAT = "%A %d %B %Y"
>>> datetime.datetime.strptime(date_txt, DATE_FORMAT)
datetime.datetime(2012, 6, 3, 0, 0)
>>>
To use customize date format:
>>> date_txt = "3 juillet"
>>> DATE_FORMAT = "%d %B"
>>> datetime.datetime.strptime(date_txt, DATE_FORMAT)
datetime.datetime(1900, 7, 3, 0, 0)
You'll realized that if the year is underspecified it's set to default at 1900
.
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agstudy
CTO - data scientist : beatyourbill I am the author of ggPMX R package and R sqlserver package You can reach me at : Twitter github
Updated on September 14, 2022Comments
-
agstudy over 1 year
Can someone please tell me how can I parse a French date in Python? Sorry if the question is a duplicate but I couldn't find one.
Here is what I have tried using the
dateutil
parser:import locale from dateutil.parser import parse as parse_dt locale.setlocale(locale.LC_TIME, 'fr_FR.UTF-8') ## first I set locale ## locale.LC_TIME, 'fr_FR.UTF-8') parse_dt('3 juillet',fuzzy= True) ## don't work give the default month ## Out[29]: datetime.datetime(2014, 10, 3, 0, 0) parse_dt(u'4 Août ',fuzzy= True) ## same thing using another month
Edit : add some context:
I am parsing dates without know in advance the format of my string. The idea is to parse many dates in fly :
parse_dt(u'Aujourd''hui ',fuzzy= True) parse_dt(u'Hier',fuzzy= True)
Edit using another library :
Using parsedatime library and some regular expression to translate french words , I can get this:
import parsedatetime import re cal = parsedatetime.Calendar() cal.parse(re.sub('juil.*' ,'jul' ,'20 juillet')) ((2015, 7, 20, 10, 25, 47, 4, 283, 1), 1)
Maybe should I generalize this to all french months?
-
alvas over 9 yearsi don't think you can parse anything properly without knowing what's the format. At most you will get hits and misses and i don't think that's what you want. most probably you've to sit down and and go through the data and get the most "catchable" formats and leave the rest alone...
-
jfs@agstudy: have you tried:
datetime.strptime(date_string, '%d %B')
? -
Jean HominalAfter inspecting the
dateutil
source code, it appears thatdateutil
does not seem to support locale-dependent date parsing. -
jfs@agstudy: I've looked at
parsedatetime
source code: it should be capable of parsing "today", "yesterday" in French if you definepdtLocale_fr
class similar topdtLocale_de
. My attempt to define it based onpdtLocale_icu
failed but it might work if you define the full locale without icu.
-
-
agstudy over 9 yearsthanks. I forget to mention that I don't kn,ow the exact format before parsing. I also can get something like
Aujourd'hui
orhier
. Looks like that I should do my personal dictionary translation. -
Romain over 3 yearsThis is super effective and much easier than setting up the locale