Print a dict sorted by values
Solution 1
One can take advantage of the fact that sort works on tuples by considering the first element as more important than the second etc:
d = { "a":4, "c":3, "b":12 }
d_view = [ (v,k) for k,v in d.iteritems() ]
d_view.sort(reverse=True) # natively sort tuples by first element
for v,k in d_view:
print "%s: %d" % (k,v)
Output:
b: 12
a: 4
c: 3
EDIT: one-liner, generator expression:
sorted( ((v,k) for k,v in d.iteritems()), reverse=True)
Output:
[(12, 'b'), (4, 'a'), (3, 'c')]
Solution 2
You can use the key
parameter of sorted
to sort by the 2nd item:
>>> d = { "a":4, "c":3, "b":12 }
>>> from operator import itemgetter
>>> for k, v in sorted(d.items(), key=itemgetter(1)):
print k, v
c 3
a 4
b 12
>>>
EDIT: one-liner, in opposite order:
>>> d = {"a": 4, "c": 3, "b": 12}
>>> [(k, v) for k, v in sorted(d.items(), key=lambda x: x[1], reverse=True)]
[('b', 12), ('a', 4), ('c', 3)]
>>>
Solution 3
>>> d = { "a":4, "c":3, "b":12 }
>>> from operator import itemgetter
>>> lst = sorted(d.iteritems(), key=itemgetter(1))
>>> for t in lst: print '%s : %d' % (t[0], t[1])
...
c : 3
a : 4
b : 12
Solution 4
Here's a solution with Python 3:
d = { "a":4, "c":3, "b":12 }
sorted(((v, k) for k, v in d.items()), reverse=True)
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Xtrato
Updated on June 19, 2021Comments
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Xtrato almost 3 years
I'm basically trying to iterate through a dict and print out the key / values from largest value to lowest. I have been searching this site and a lot of people are using lambda but I'm not really sure how its working so I'm trying to avoid it for now.
dictIterator = iter(sorted(bigramDict.iteritems())) for ngram, value in dictIterator: print("There are " + str(value) + " " + ngram)
Looking over the code above I assumed it would make an iterator which returns the key/value pairs in order from largest to smallest but it's not.
Can anyone see what the problem is? or another method of doing this?
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Alex Emelin almost 12 yearslook at this: stackoverflow.com/questions/613183/…
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tegan over 5 yearsthanks! Python 3 one-liner:
sorted( ((v,k) for k,v in d.items()), reverse=True)
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Jean Coiron over 4 yearsThis works but it loops X times on the whole dict, where X is the len() of the dict. It might waste resources.
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Ward W over 4 yearsThese sorts the opposite way. Mind editing to reverse the order (so that it goes from largest to smallest)? Thanks!