Round Percentages PHP

Question

I'm currently dividing two values in order to get the percentage from the actual count and the total count for my application.

I am using the following formula:

echo ($fakecount / $totalcount) * 100;

That is giving me a value like: 79.2312313. I would perefer a value like 79%.

I have tried the following:

echo round($fakecount / $totalcount) * 100; 

this doesn't seem to work correctly.

Any suggestions?

Solution 1

try,

echo (int)($fakecount * 100 / $totalcount + .5);

This works because adding 0.5 increases the integer part by 1 if the decimal part is >= .5

or,

round ($fakecount * 100 / $totalcount); 

Note that, I'm doing the multiplication by 100 before the division to better preserve the precision.

Solution 2

You need to multiply by 100 before you round, not after:

echo round($fakecount * 100 / $totalcount);

You are calculating $fakecount / $totalcount, which will be a number between 0 and 1, then you round that, so you get either 0 or 1, then you multiply by 100, giving either 0 or 100 for your percentage.

Solution 3

echo intval(($fakecount / $totalcount) * 100); 

Or you can use

echo floor(($fakecount / $totalcount) * 100);  //Round down

Or

echo ceil(($fakecount / $totalcount) * 100);  // Round Up

Comments

[Samuel Cook]

add the * 100 inside of the round: echo round($fakecount / $totalcount * 100);

[rjmunro]

intval() is the same as floor(). Use round()

[rjmunro]

Casting to int is the same as floor(). Use round() to get the nearest value.

[Fallen]

@rjmunro my one will return the same value as round() as I added 0.5 before type casting :)

[rjmunro]

Sorry, didn't spot that. Are you sure that the performace of casting to int is better than using round() by enough of a margin to be faster than the extra addition?

[Fallen]

@rjmunro: I'm not sure about the runtime performance. but not all languages have round() function, but casting to int after adding 0.5 is a good way to do in all languages. and if it's about runtime I think the difference would be negligible as round function has to do something similar (I don't know exactly how round() rounds a number)