setTimeout calling function inside function - Scope-Issue
19,248
Solution 1
function general(){
function saysomething(){
console.log('hi there');
}
setTimeout(saysomething, 1000);
}
Solution 2
Not positive this is what you mean but you can pass the variables when you call the function in the setTimeout
function f1(){
var a='1';
var b='b';
setTimeout(function(){f2(a,b);},1000)
}
function f2(a,b){
alert(a + b);
}
f1();
Author by
Julian
Frontend Dev at 3ev. Designer, Animator, Artist and generally a fan of building stuff.
Updated on June 04, 2022Comments
-
Julian almost 2 years
So, the problem is that I have a function inside a function that needs to be called by setTimeout. That doesn't work however because setTimeout will assume that the function it calls has the root as its' scope.
Any idea how I could solve this without changing the scope of the function?
Edit:
Here is what I mean:
function general(){ function saysomething(){ console.log('hi there'); } setTimeout("saysomething();", 1000); }
The setTimeout fails..