Shell script to pass multiple arguments with options in command line
20,922
I believe using getopts
is a better solution for advance use, when you need flexibility on the amount of arguments passed.
This is a working example:
if (($# == 0)); then
echo "Please pass argumensts -p <pkg1><pkg2>... -m <email1><email2>.."
exit 2
fi
while getopts ":p:m:" opt; do
case $opt in
p)
echo "-p was triggered, Parameter: $OPTARG" >&2
PKGS=$OPTARG
;;
m)
echo "-m was triggered, Parameter: $OPTARG" >&2
MAIL=$OPTARG
;;
\?)
echo "Invalid option: -$OPTARG" >&2
exit 1
;;
:)
echo "Option -$OPTARG requires an argument." >&2
exit 1
;;
esac
done
echo "go thru selection"
for PKG in $PKGS;
do
echo "ARG_PKG: $PKG"
done
echo "go thru selection email"
for M in $MAIL;
do
echo "ARG_MAIL: $M"
done
exit 0
ref.. http://wiki.bash-hackers.org/howto/getopts_tutorial
OUTPUT:
bash t -p "pkg1 pkg2 pkg3" -m "[email protected] [email protected]"
-p was triggered, Parameter: pkg1 pkg2 pkg3
-m was triggered, Parameter: [email protected] [email protected]
go thru selection
ARG_PKG: pkg1
ARG_PKG: pkg2
ARG_PKG: pkg3
go thru selection email
ARG_MAIL: [email protected]
ARG_MAIL: [email protected]
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Comments
-
Beginner over 1 year
I have the script, I need to execute this script like this:
./create_endpoint.sh --controller-ip 10.20.20.1 --controller-name User1.
But its executing like this:
./create_endpoint.sh 10.20.20.1 User1
The script:
CONTROLLER_IP="" CONTROLLER_NAME="" if [ "$#" -eq 2 ] then CONTROLLER_IP=$1 CONTROLLER_NAME=$2 else echo "Usage : create_endpoint.sh --controller-ip <Controller IP> --controller-name" exit 1 fi echo $CONTROLLER_IP echo $CONTROLLER_NAME
-
Beginner over 6 yearsyeah, like above. Can you give some examples. Sometime I pass one argument or three arguments depends upon the requirement. how can i validate and execute
-
Suresh Raju over 6 yearsif no of arguments will vary then check the $# -ge 2. Then check for not-null values.