simpleXML get node child based on attribute
Solution 1
Simply loop the poster elements and remember to cast the attribute values to strings, since you want to compare them (and probably output them) as strings:
$xml = simplexml_load_file('PosterData.xml');
foreach ($xml->poster as $poster) {
if ((string) $poster['id'] == 'minwage') {
echo (string) $poster->full_image['url'];
}
}
Solution 2
You should be able to use SimpleXMLElement::xpath() to run an xpath query on a simple XML document.
$xml = simplexml_load_file('PosterData.xml');
$main_url = $xml->xpath('name[@id="minwage"]/full_image')[0];
echo $main_url;
Solution 3
You can use:
$object = simplexml_load_string('<data><poster name="E-Verify" id="everify"><full_image url="e-verify-swa-poster.jpg"/><full_other url=""/></poster><poster name="Minimum Wage" id="minwage"><full_image url="minwage.jpg"/><full_other url="spa_minwage.jpg"/></poster></data>');
foreach ($object as $value) {
echo "URL: ".$value->full_image->attributes();
echo "<br>";
}
Either use simplexml_load_file('Some external file.xml')
if calling external file.
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Denoteone
I have 12 years of professional experience efficiently coding websites, web applications, and CMS plugins using current web technologies like PHP, Angular 2, and CSS(3) to list a few examples. Building state-of-the-art, easy to use, user-friendly websites and applications that have valid and efficient code is truly a passion of mine In addition to my knowledge base, I actively seek out new technologies and stay up-to-date on industry trends and advancements. Denoteone @ Miaou
Updated on June 04, 2022Comments
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Denoteone almost 2 years
I am trying to parse out the value of a node I am referencing by one of its attributes. but I am not sure of the syntax
XML:
<data> <poster name="E-Verify" id="everify"> <full_image url="e-verify-swa-poster.jpg"/> <full_other url=""/> </poster> <poster name="Minimum Wage" id="minwage"> <full_image url="minwage.jpg"/> <full_other url="spa_minwage.jpg"/> </poster> </data>
here is where I want to get the url value of full_image where poster id equal to minwage:
$xml = simplexml_load_file('PosterData.xml'); $main_url = $xml->full_image[name] where poster[id] = "minwage"; //something like that. echo $main_url; Result: minwage.jpg
If anyone has any resources that cover this stuff please share.
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Denoteone about 12 yearsThat worked like a charm. I was def over thinking the process. +1
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Denoteone about 12 yearsThis is how I was trying originally. thanks for the info.
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Select0r over 8 yearsThis is a lot more elegant than just looping and should be the excepted answer.
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buck1112 over 6 yearsI've been trying to make this code work, by duplicating the code on my localhost, yet I get "Undefined Offset: 0" Please see: stackoverflow.com/questions/48154956/…
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Jordan about 6 yearsShouldn't "name" in 'name[@id="minwage"]' be "poster"? Since the element is a "poster" element?