Split string and just get number in python?

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Solution 1

If all your numbers are positive integers, you can do that without regular expressions by using the isdigit() method:

>>> text = "GoTo: 7018 6453 12654\n"
>>> [token for token in text.split() if token.isdigit()]
['7018', '6453', '12654']

Solution 2

>>> re.findall(r'\d+', 'GoTo: 7018 6453 12654\n')
['7018', '6453', '12654']

Solution 3

>>> import re
>>> re.findall("[0-9]+", "GoTo: 7018 6453 12654\n")
['7018', '6453', '12654']
>>> 

Solution 4

You can follow your current method in sample 1 along with this code:

filter (lambda a: a != '', match1)

Solution 5

Try this:

import re
splitter = re.compile(r'\d+')
match1 = splitter.findall("GoTo: 7018 6453 12654\n")
print match1
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Updated on May 14, 2022

Comments

  • Am1rr3zA
    Am1rr3zA 15 days

    I have a string like "GoTo: 7018 6453 12654\n" I just want get the number something like this ['7018', '6453', '12654'], I tries regular expression but I can't split string to get just number here is my code:

    Sample 1:

    splitter = re.compile(r'\D');
    match1 = splitter.split("GoTo: 7018 6453 12654\n")
    
    my output is: ['', '', '', '', '', '', '', '', '7018', '6453', '12654', '']
    

    Sample 2:

    splitter = re.compile(r'\W');
    match1 = splitter.split("GoTo: 7018 6453 12654\n")
    
    my output is: ['GoTo', '', '7018', '6453', '12654', '']