Accessing a Pandas index like a regular column
Solution 1
Index has a special meaning in Pandas. It's used to optimise specific operations and can be used in various methods such as merging / joining data. Therefore, make a choice:
- If it's "just another column", use
reset_index
and treat it as another column. - If it's genuinely used for indexing, keep it as an index and use
df.index
.
We can't make this choice for you. It should be dependent on the structure of your underlying data and on how you intend to analyse your data.
For more information on use of a dataframe index, see:
- What is the performance impact of non-unique indexes in pandas?
- What is the point of indexing in pandas?
Solution 2
You could also use df.index.get_level_values
if you need to access a (index) column by name. It also works with hierarchical indices (MultiIndex
).
>>> df.index.get_level_values('name')
Index(['a', 'b', 'c', 'd', 'e'], dtype='object', name='name')
Solution 3
Instead of using reset_index
, you could just copy the index to a normal column, do some work and then drop the column, for example:
df['tmp'] = df.index
# do stuff based on df['tmp']
del df['tmp']
kuzzooroo
Updated on July 09, 2022Comments
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kuzzooroo almost 2 years
I have a Pandas DataFrame with a named index. I want to pass it off to a piece off code that takes a DataFrame, a column name, and some other stuff, and does a bunch of work involving that column. Only in this case the column I want to highlight is the index, but giving the index's label to this piece of code doesn't work because you can't extract an index like you can a regular column. For example, I can construct a DataFrame like this:
import pandas as pd, numpy as np df=pd.DataFrame({'name':map(chr, range(97, 102)), 'id':range(10000,10005), 'value':np.random.randn(5)}) df.set_index('name', inplace=True)
Here's the result:
id value name a 10000 0.659710 b 10001 1.001821 c 10002 -0.197576 d 10003 -0.569181 e 10004 -0.882097
Now how am I allowed to go about accessing the
name
column?print(df.index) # No problem print(df['name']) # KeyError: u'name'
I know there are workaround like duplicating the column or changing the index to something else. But is there something cleaner, like some form of column access that treats the index the same way as everything else?
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kuzzooroo over 5 yearsSay I have a library function that takes a DataFrame and creates a scatter plot based on it. It labels points in the plot based on the column of your choice, currently specified as a string. Now a use case has come up where it would be useful for the labels to be based on the index of a certain DataFrame. The index of this DataFrame is undoubtedly special, as you say. It's just in the context of this one function where it would be convenient to treat the index like a regular column, and I'm wondering if it can be done transparently.
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jpp over 5 years@kuzzooroo, I suggest you ask a separate question with a minimal reproducible example of the problem you are facing. The example you gave in your question, for example, doesn't show any problem with using
df.index
. The methods available topd.Index
objects are different to those available topd.Series
objects so we need to see your code to determine the issue. -
Peruz about 4 yearsI like this solution too, in the end column and index serve different purposes, just keep both if needed.
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guibar over 3 yearsOne wonders what the point of giving the index a name is, if it can't be used as such like other column names ...
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jpp over 3 years@guibar, you can with pd.DataFrame.query
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Keto almost 3 yearsThis is not really a solution and your answer is out of scope. So what you're implying is that "no it's not possible because Pandas did not build an interface to interact the index like a column". If yes, then let this be the answer. Now a natural followup question is why not? We've seen other software being able to do this like SQL .
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william_grisaitis about 2 yearsthis is not an answer to the OP's question. it's a justification of why the problem exists in the first place... which is as a pandas user of more than a decade now, still confuses me why the API works this way.
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jpp about 2 years@grisaitis, You have a couple of options: provide a better answer, or propose a Pandas code update to development team.
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william_grisaitis about 2 years@jpp thanks. i've upvoted answers and github issues that i believe do that.