Add to integers in a list

190,303

Solution 1

Here is an example where the things to add come from a dictionary

>>> L = [0, 0, 0, 0]
>>> things_to_add = ({'idx':1, 'amount': 1}, {'idx': 2, 'amount': 1})
>>> for item in things_to_add:
...     L[item['idx']] += item['amount']
... 
>>> L
[0, 1, 1, 0]

Here is an example adding elements from another list

>>> L = [0, 0, 0, 0]
>>> things_to_add = [0, 1, 1, 0]
>>> for idx, amount in enumerate(things_to_add):
...     L[idx] += amount
... 
>>> L
[0, 1, 1, 0]

You could also achieve the above with a list comprehension and zip

L[:] = [sum(i) for i in zip(L, things_to_add)]

Here is an example adding from a list of tuples

>>> things_to_add = [(1, 1), (2, 1)]
>>> for idx, amount in things_to_add:
...     L[idx] += amount
... 
>>> L
[0, 1, 1, 0]

Solution 2

You can append to the end of a list:

foo = [1, 2, 3, 4, 5]
foo.append(4)
foo.append([8,7])    
print(foo)            # [1, 2, 3, 4, 5, 4, [8, 7]]

You can edit items in the list like this:

foo = [1, 2, 3, 4, 5]
foo[3] = foo[3] + 4     
print(foo)            # [1, 2, 3, 8, 5]

Insert integers into the middle of a list:

x = [2, 5, 10]
x.insert(2, 77)
print(x)              # [2, 5, 77, 10]

Solution 3

fooList = [1,3,348,2]
fooList.append(3)
fooList.append(2734)
print(fooList) # [1,3,348,2,3,2734]

Solution 4

If you try appending the number like, say listName.append(4) , this will append 4 at last. But if you are trying to take <int> and then append it as, num = 4 followed by listName.append(num), this will give you an error as 'num' is of <int> type and listName is of type <list>. So do type cast int(num) before appending it.

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Updated on July 31, 2022

Comments

  • fangus
    fangus almost 2 years

    I have a list of integers and I was wondering if it would be possible to add to individual integers in this list.