Adding characters to beginning and end of InputStream in Java

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You want a SequenceInputStream and a couple of ByteArrayInputStreams. You can use String.getBytes to make the bytes for the latter. SequenceInputStream is ancient, so it's a little clunky to use:

InputStream middle ;
String beginning = "Once upon a time ...\n";
String end = "\n... and they lived happily ever after.";
List<InputStream> streams = Arrays.asList(
    new ByteArrayInputStream(beginning.getBytes()),
    middle,
    new ByteArrayInputStream(end.getBytes()));
InputStream story = new SequenceInputStream(Collections.enumeration(streams));

If you have a lot of characters to add, and don't want to convert them to bytes en masse, you could put them in a StringReader, then use a ReaderInputStream from Commons IO to read them as bytes. But you would need to add Commons IO to your project to do that. Exact code for that is left as an exercise for the reader.

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Updated on June 05, 2022

Comments

  • pqn
    pqn almost 2 years

    I have an InputStream which I need to add characters to the beginning and end of, and should end up with another variable of type InputStream. How could I easily do this?

  • pqn
    pqn over 12 years
    More detail please? Thanks for the handy class names.
  • Tom Anderson
    Tom Anderson over 12 years
    How do you write characters to an InputStream?
  • Alex
    Alex over 12 years
    -1, Write the ending characters to your new InputStream. -> you can't write characters to an InputStream
  • JB Nizet
    JB Nizet over 12 years
    If you read the javadoc for those classes, it's pretty obvious. Construct a first ByteArrayInputStream (let's call it head) containing the bytes of the beginning, a second one containing the bytes of the end (let's call it tail), and build a SequenceInputStream from the head, the original input stream, and the tail.
  • rossum
    rossum over 12 years
    Whoops! Reboots brain. Write to an output stream, backed by a byte array as Greg says. Extract the backing array and reopen as an input stream. Thanks for the correction.
  • pqn
    pqn over 12 years
    Also, it should be Arrays.asList and not Collections.asList.
  • Fabian Tamp
    Fabian Tamp almost 10 years
    -1, this would've been better represented with code and isn't efficient for large streams.
  • rossum
    rossum almost 10 years
    @Fabian I read this question as homework, hence I gave help, but not code. YMMV.