AJAX call and clean JSON but Syntax Error: missing ; before statement
Solution 1
JSONP is not JSON. A JSONP response would consist of a JavaScript script containing only a function call (to a pre-defined function) with one argument (which is a JavaScript object literal conforming to JSON syntax).
The response you are getting is JSON, not JSONP so your efforts to handle it as JSONP fail.
Change dataType: 'jsonp'
to dataType: 'json'
(or remove the line entirely, the server issues the correct content-type so you don't need to override it).
Since your script is running on a different origin to the JSON then you will also need to take steps (most, but not all, of which require that you control the host serving the JSON) to work around the same origin policy.
Solution 2
The error is because it is returning JSON not JSONP.
JSONP is supposed to look like
someCallBackString({ The Object });
Solution 3
Here is the working example
$.ajax({
type: 'GET',
url: 'http://xxx.amazonaws.com/file.json',
dataType: 'jsonp',
jsonpCallback: 'callback',
success: function(json){
console.log(json);
}
});
And you should put callback
in the beginning of your file.json
like :
callback({"item":{".......
Solution 4
As epascarello pointed out, the JSONP response must be sent like:
callBackFunction({ JSON Object })
And the caller function can then be setup like:
var url = "http://someremoteurl.com/json";
$.getJSON(url + "?callback=?", null, function(data) {
callBackFunction(data);
});
Then you can loop over the response data as:
function callBackFunction(data)
{
console.log(data);
}
Solution 5
If you're using "callback=?" parameter, your response on the server side should look like this:
$_callback = $_GET['callback'];
echo $_callback . '(' . json_encode(YOUR_VARIABLE) . ');';
If "callback=?" parameter is not defined, your response should look like this:
echo '[' . json_encode($_return_array) . ']';
JZweige
Updated on July 09, 2022Comments
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JZweige almost 2 years
I am making a cross domain JSONP call using this code:
jQuery.ajax({ async: true, url: 'http://mnews.hostoi.com/test.json', dataType: 'jsonp', method: "GET", error: function (jqXHR, textStatus, errorThrown) { console.log(textStatus + ': ' + errorThrown); }, success: function (data, textStatus, jqXHR) { if (data.Error || data.Response) { exists = 0; } } });
When debugging in Firebug, I get the following error:
SyntaxError: missing ; before statement
However, when I pass my json object (available through the link in the JQ code) through a tool like jsonlint.com, it says it is valid JSON. And I don't find any anomalies either. How could it be returning a syntax error? Is it some JSONP detail I am not getting or what?
JSON Sample
{"news":[ { "sentences": [ "Neuroscientists have discovered abnormal neural activity...", "The researchers found that these mice showed many symptoms...", "\"Therefore,\" the study authors say, \"our findings provide a novel.." ], "summaryId": "ZJEmY5", "title": "Abnormal neural activity linked to schizophrenia" }]}
Thanks in advance.
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JZweige over 10 yearsMy script is running on a different origin, yes. I will try to implement CORS, using the link your provided. Thanks.
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user2422869 almost 9 yearsThe question wasn't about Ruby at all.