Android : Check 3G or Wifi network is ON or Available or not on android Device

Question

How to check that network is available or not on android device programmatically, which throws a message or toast message when we are trying to connect with a network such as Wifi & 3G.

Solution 1

TO check whether network i.e 3G or WiFi is available or not we can use below methods to verify before starting our activities.

ConnectivityManager manager = (ConnectivityManager) getSystemService(CONNECTIVITY_SERVICE);

//For 3G check
boolean is3g = manager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE)
            .isConnectedOrConnecting();
//For WiFi Check
boolean isWifi = manager.getNetworkInfo(ConnectivityManager.TYPE_WIFI)
            .isConnectedOrConnecting();

System.out.println(is3g + " net " + isWifi);

if (!is3g && !isWifi) 
{ 
Toast.makeText(getApplicationContext(),"Please make sure your Network Connection is ON ",Toast.LENGTH_LONG).show();
} 
 else 
{ 
        " Your method what you want to do "
} 

Hope this will help someone.

Solution 2

final ConnectivityManager connMgr = (ConnectivityManager)
    this.getSystemService(Context.CONNECTIVITY_SERVICE);

    final android.net.NetworkInfo wifi =
    connMgr.getNetworkInfo(ConnectivityManager.TYPE_WIFI);

    final android.net.NetworkInfo mobile =
    connMgr.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);

    if( wifi.isAvailable() && wifi.getDetailedState() == DetailedState.CONNECTED){
        Toast.makeText(this, "Wifi" , Toast.LENGTH_LONG).show();
    }
    else if( mobile.isAvailable() && mobile.getDetailedState() == DetailedState.CONNECTED ){
        Toast.makeText(this, "Mobile 3G " , Toast.LENGTH_LONG).show();
    }
    else
    {   
        Toast.makeText(this, "No Network " , Toast.LENGTH_LONG).show();
    }

this code check if you are with wifi or 3g or nothing , in the case of wifi on but not connected to a net or 3g have signal problem it detect this details, with DetailedStates

Solution 3

You can use this method to check whether your internet connection is 2G, 3G or 4G:

public String getNetworkClass(Context context) {
    TelephonyManager mTelephonyManager = (TelephonyManager)
            context.getSystemService(Context.TELEPHONY_SERVICE);
    int networkType = mTelephonyManager.getNetworkType();
    switch (networkType) {
        case TelephonyManager.NETWORK_TYPE_GPRS:
        case TelephonyManager.NETWORK_TYPE_EDGE:
        case TelephonyManager.NETWORK_TYPE_CDMA:
        case TelephonyManager.NETWORK_TYPE_1xRTT:
        case TelephonyManager.NETWORK_TYPE_IDEN:
            return "2G";
        case TelephonyManager.NETWORK_TYPE_UMTS:
        case TelephonyManager.NETWORK_TYPE_EVDO_0:
        case TelephonyManager.NETWORK_TYPE_EVDO_A:
        case TelephonyManager.NETWORK_TYPE_HSDPA:
        case TelephonyManager.NETWORK_TYPE_HSUPA:
        case TelephonyManager.NETWORK_TYPE_HSPA:
        case TelephonyManager.NETWORK_TYPE_EVDO_B:
        case TelephonyManager.NETWORK_TYPE_EHRPD:
        case TelephonyManager.NETWORK_TYPE_HSPAP:
            return "3G";
        case TelephonyManager.NETWORK_TYPE_LTE:
            return "4G";
        default:
            return "Unknown";
    }
}

And using following method you can check if internet is available or not, and get whether you are accessing the internet via a mobile network or WiFi:

public String getNetworkType(Context context){
    String networkType = null;
    ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = connectivityManager.getActiveNetworkInfo();
    if (activeNetwork != null) { // connected to the internet
        if (activeNetwork.getType() == ConnectivityManager.TYPE_WIFI) {
                networkType = "WiFi";
        } else if (activeNetwork.getType() == ConnectivityManager.TYPE_MOBILE) {
            networkType = "Mobile";
        }
    } else {
        // not connected to the internet
    }
    return networkType;
}

Solution 4

This work for me

NetworkInfo networkInfo = connMgr.getActiveNetworkInfo();   
String name networkInfo.getTypeName();  

Solution 5

Rahul Baradia's answer includes manager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE) and it's deprecated.

Below is an improved solution for the latest Android SDK.

ConnectivityManager connManager = (ConnectivityManager) context.getSystemService(CONNECTIVITY_SERVICE);
        boolean is3gEnabled = false;
        if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {
            Network[] networks = connManager.getAllNetworks();
            for(Network network: networks)
            {
                NetworkInfo info = connManager.getNetworkInfo(network);
                if(info!=null) {
                    if (info.getType() == ConnectivityManager.TYPE_MOBILE) {
                        is3gEnabled = true;
                        break;
                    }
                }
            }
        }
        else
        {
            NetworkInfo mMobile = connManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
            if(mMobile!=null)
                is3gEnabled = true;
        }

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Comments

[Rahul Baradia]

rahulbaradiaa.blogspot.in/2012/07/… u can get the information here too..

[benoffi7]

Nullpointer in boolean is3g = manager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE).isCo‌​nnectedOrConnecting(‌​);

[Denis Gladkiy]

Why the switched off wifi (or 3G) is an error (Log.e(TAG, "WI-FI Network not Found")) 0_0? It is a valid case for a phone and for many apps that can do work (maybe part of it) without it. Why so many logging in such utility and not mission-critical code?

[Kikiwa]

As @benoffi7 said, you have to test that manager.getNetworkInfo(ConnectivityManager.*) is not null before to call the isConnectedOrConnecting() method.

[Anwar]

getInfoNetwork(int) is now deprecated. Just for the record (see this StackOverflow answer for an updated version).

[HungNM2]

getNetworkInfo() is depreciated now, because for example: in case, there are 2 cellular networks on device.

[kemdo]

this return only that connected to network type, not return the type that enabled by user.