angular js: Prevent Bootstrap Modal from disappearing when clicking outside or pressing escape?

Question

Am using the angular bootstrap to present a modal. But my requirement is to prevent pop-up dismissal when clicking outside the modal, or when the escape key is pressed.

I followed the tutorial on the angular bootstrap site :http://angular-ui.github.io/bootstrap/

Solution 1

Use:

backdrop: 'static'

backdrop - controls presence of a backdrop. Allowed values: true (default), false (no backdrop), 'static' - backdrop is present but modal window is not closed when clicking outside of the modal window.

For example:

$modal.open({
      templateUrl: 'myModalContent.html',
      controller: ModalInstanceCtrl,
      backdrop: 'static'
    })

Solution 2

Add both backdrop: static and keyboard: false to your modal options. The first one disables the background click, the second one the escape key.

backdrop: 'static' - backdrop is present but modal window is not closed when clicking outside of the modal window.

keyboard - indicates whether the dialog should be closable by hitting the ESC key, defaults to true.

Example:

$modal.open({
  templateUrl: 'template.html',
  controller: TheController,
  backdrop: 'static',
  keyboard: false
})

See the docs for more information.

Solution 3

"backdrop - controls presence of a backdrop. Allowed values: true (default), false (no backdrop), 'static' - backdrop is present but modal window is not closed when clicking outside of the modal window." - in http://angular-ui.github.io/bootstrap/#/modal

Try:

<div ng-controller="ModalDemoCtrl" data-backdrop="static">
...
</div>

Comments

[Jay Jay Jay]

Works without a doubt as the answer below confirms

[boardlemur]

This should be the accepted answer as it resolves both of the requirements as outlined by the OP.

[Almog Cohen]

As said, the best and more broad answer