array_sum() expects parameter 1 to be array

php arrays

14,585

Solution 1

Hmm, weird, i dont know what the error is in your code, but try this out :

$VoteValue = array();
for ($i=0; $i<=30; $i++) {
           $VoteValue[] = $i;
       }

       $Total = array_sum($VoteValue);
       echo "<br /><br />Total Vote = $Total <br />";

Solution 2

Have you tried initializing $VoteValue with

$VoteValue = array();

As a total aside, the sum from 0 to n = ( n * (n+1) ) / 2.

Solution 3

try this way. I hope to be helpful

$VoteValue = [];

for ($i=0; $i<=30; $i++) {
     array_push($VoteValue, $i);
}

$Total = array_sum($VoteValue);

echo "<br /><br />Total Vote = $Total <br />";

Solution 4

i'v tried,on the ubuntu11.04 with lampp. no errors.

Total Vote = 465

maybe the php problem.

View more solutions

14,585

Author by

Ray

A coder with the passion of 'Never Stop Learning'.

Updated on November 21, 2022

Comments

Ray over 1 year
Need someone to help me to crack the following.

On my local machine, i'm running MAMP on my Mac. I have the following code:
```
   $x=0;
   for ($i=0; $i<=30; $i++) {
       $VoteValue[$x] = $i;
       $x++;
   }

   $Total = array_sum($VoteValue);
   echo "<br /><br />Total Vote = $Total <br />";
```
The above code works and run fine on my local machine. But, when I uploaded it to my production server, I get the following warning prompts:
```
Warning: array_sum() expects parameter 1 to be array, null given in /home/RIP/public_html/RIPVote.php on line 7
```
and it doesn't return and show the output value due to the warning error. How do i get rid of this?

Please advice and looking forward to hear from you guys soon. Appreciate and thanks.
- Oliver Charlesworth over 12 years
  
  Do a var_dump immediately before you call array_sum...
- Kieran over 12 years
  
  Not sure if this is necessary, but have you tried adding $VoteValue = array() before the loop?
- Ray over 12 years
  
  Thanks Oli and Kieran, got it sorted
Wrikken over 12 years

Would work indeed if $VoteValue is a string before, short explanation: $VoteValue[n]=$something would then replace the n-th character with the first character of $something, and just remain an (altered) string.
Ray over 12 years

Hi Pheonix, Thanks for your precise solution and example. It works now. Much appreciated really. Also, thanks for rest for the examples as well as i have tried it.
Ray over 12 years

Hi craigmj and Wrikken, thanks for the suggestions. Got it sorted.
Chrisvin Jem almost 5 years

Your answer provides no additional information or value to the answer already provided by craigmj and Pheonix.