AS3: Checking if a variable is of the Object type
Solution 1
You should try to use this functions - getQualifiedClassName
and typeof
. Here's a code showing how they behave for different data types you've listed, see the difference for the Array and Numbers especially:
Code:
var o = new Array();
trace ("var o = new Array()");
trace (getQualifiedClassName(o));
trace (typeof(o));
var o = new Object();
trace ("var o = new Object();");
trace (getQualifiedClassName(o));
trace (typeof(o));
var o = new String();
trace ("var o = new String()");
trace (getQualifiedClassName(o));
trace (typeof(o));
var o = new Number()
trace ("var o = new Number()");
trace (getQualifiedClassName(o));
trace (typeof(o));
var o = 3.14;
trace ("var o = 3.14");
trace (getQualifiedClassName(o));
trace (typeof(o));
Result:
var o = new Array()
Array
object
var o = new Object();
Object
object
var o = new String()
String
string
var o = new Number()
int
number
var o = 3.14
Number
number
I assume getQualifiedClassName would be what you're looking for, which is in the flash utils package:
import flash.utils.getQualifiedClassName;
Solution 2
Try something based around one of these:
if (variable.constructor.toString().match(/object/i) == 'Object')
if (variable.constructor.toString().indexOf("Object") != -1)
If the object is an Object() the constructor string will be something like
function Object() { ... }
so you can check for that.
Solution 3
You can also use getQualifiedSuperclassName
which returns null
for the Object
type as it doesn't have a super class:
public static function isObject( obj:* ):Boolean
{
if ( obj == null )
return false;
return ( getQualifiedSuperclassName( obj ) == null );
}
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Tapio Saarinen
Updated on October 16, 2020Comments
-
Tapio Saarinen over 3 years
I want to do something like this in Actionscript 3:
if(variable is Object) ...; else ...;
Where
variable
could be aString()
,Number()
,Array()
,Object()
...Currently the above check returns true for all of these types, which makes sense. I only want it to return true for objects made with
new Object()
, however.Any help would be much appreciated!
-
Tapio Saarinen over 14 yearsYep, I actually found out about getQualifiedClassName shortly after, and it is indeed what I was looking for. Thanks for the reply!