awk + Need to print everything (all rest fields) except $1 and $2

Question

I have the following file and I need to print everything except $1 and $2 by awk

File:

INFORMATION DATA 12 33 55 33 66 43 
INFORMATION DATA 45 76 44 66 77 33 
INFORMATION DATA 77 83 56 77 88 22
...

the desirable output:

 12 33 55 33 66 43 
 45 76 44 66 77 33 
 77 83 56 77 88 22
...

Solution 1

Well, given your data, cut should be sufficient:

cut -d\  -f3- infile

Solution 2

Although it adds an extra space at the beginning of each line compared to yael's expected output, here is a shorter and simpler awk based solution than the previously suggested ones:

awk '{$1=$2=""; print}'

or even:

awk '{$1=$2=""}1'

Solution 3

$ cat t
INFORMATION DATA 12 33 55 33 66 43
INFORMATION DATA 45 76 44 66 77 33
INFORMATION DATA 77 83 56 77 88 22
$ awk '{for (i = 3; i <= NF; i++) printf $i " "; print ""}' t 
12 33 55 33 66 43 
45 76 44 66 77 33 
77 83 56 77 88 22 

Solution 4

danbens answer leaves a whitespace at the end of the resulting string. so the correct way to do it would be:

awk '{for (i=3; i<NF; i++) printf $i " "; print $NF}' filename

Solution 5

If the first two words don't change, probably the simplest thing would be:

awk -F 'INFORMATION DATA ' '{print $2}' t

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