Bash: How to invoke command and store the result in a variable?
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Solution 1
You most likely want to use batch mode (-B) and disable column names (--disable-column-names) for non-interactive mysql output:
out=$(mysql -B -db mydb -uanon -ppwd --disable-column-names -e "select count(*) from table1";)
Solution 2
$ A=$(mysql -uanon -ppwd -db mydb -e "select count(*) from table1")
$ echo $A
In other words, use the $() syntax.
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Author by
Sergey Brill
Updated on July 09, 2022Comments
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Sergey Brill almost 2 years
Basically I want to be able to invoke a given command, in this case
mysql -uanon -ppwd -db mydb -e "select count(*) from table1"
. And then take this commands result (the count on that table) and place it in a variable in bash script. What is the simplest way to achieve this? -
Sudhanshu Mishra almost 7 yearsFor Linux newbies, make sure there are no spaces between variable name, the = sign and the expression that follows. Bad things can happen.