Binary file in npm package

15,749

Solution 1

Actually, you can put your myapp.js file into bin.
So, the bin key in package.json file should be like this :

"bin": { "myapp" : "<relative_path_to_myapp.js>/lib/myapp.js" }

At the first line in myapp.js, you must add this shebang line :

#!/usr/bin/env node

It tells the system to use node to run myapp.js.


... Or if you don't want to call myapp.js directly, you can create a script like this to be your executable file :

#!/usr/bin/env node

var myapp = require('<relative_path_to_myapp.js>/myapp.js');
myapp.doSth();

and in package.json :

"bin" : { "myapp" : "<relative_path_to_the_script>/script.js" }

By doing this either way, you can avoid finding the path to your nodemodule.


But... if you insist to use your old myapp bash script, then you can find the path to the module with this :

myapp_path=$( npm explore -g myapp -- "pwd" )

Hope these help :D

Solution 2

https://docs.npmjs.com/files/package.json#bin

From the above link:

...

To use this, supply a bin field in your package.json which is a map of command name to local file name. On install, npm will symlink that file into prefix/bin for global installs, or ./node_modules/.bin/ for local installs.

For example, myapp could have this:

{ "bin" : { "myapp" : "./cli.js" } }

So, when you install myapp, it’ll create a symlink from the cli.js script to /usr/local/bin/myapp.

...

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ciembor
Author by

ciembor

Updated on June 18, 2022

Comments

  • ciembor
    ciembor almost 2 years

    I try to create an npm package, which can be started as a command from shell. I have package.json

    {
      "name": "myapp",
      "version": "0.0.6",
      "dependencies": {
        "async": "",
        "watch": "",
        "node-promise": "",
        "rmdir": "",
        "should": "",
        "websocket": ""
      },
      "bin": "myapp"
    }
    

    and myapp

    #!/bin/bash
    
    path=`dirname "$0"`
    file="/myapp.js"
    
    node $path$file $1 &
    

    But I get an error:

    module.js:340
        throw err;
              ^
    Error: Cannot find module '/usr/local/bin/myapp.js'
        at Function.Module._resolveFilename (module.js:338:15)
        at Function.Module._load (module.js:280:25)
        at Function.Module.runMain (module.js:497:10)
        at startup (node.js:119:16)
        at node.js:902:3
    

    The problem is that myapp.js is in another directory. How can I get this directory name from my script? Or maybe there is better way to do this?