bubble sort a character array in alphabetic order in c
Solution 1
Fixing your code
First of all, there are some pretty serious fundamental issues with your code. Before we tackle those though, let's just fix what you have so far. Your sorting loop seemed to be half sorting the a array and half sorting the b array. you also never initialized the b array to contain any values. Here is a corrected version of your code:
#define CLASS_SIZE 10
#include <stdio.h>
void bubbleSortAWriteToB(const char a[], char * b[]);
int main(void){
int i;
// initialize array
char * s_letters[CLASS_SIZE];
char letters[CLASS_SIZE] = {'a','r','p','b','r','c','x','e','w','j'};
// sort array
bubbleSortAWriteToB(letters,s_letters);
// print sorted array
for (i=0;i<CLASS_SIZE;i++){
printf("%c\n", *s_letters[i]);
}
return 0;
}
void bubbleSortAWriteToB(const char a[], char * b[]){
char * temp;
int i,j;
// initialize b array to hold pointers to each element in a
for (i=0;i<CLASS_SIZE;i++){
b[i] = (char *)(a) + i;
}
// in-place sort the b array
for(i=0;i<CLASS_SIZE;i++){
for(j=i+1;j<CLASS_SIZE-1;j++){
if(*b[j-1]>*b[j]){
temp = b[j];
b[j] = b[j-1];
b[j-1] = temp;
}
}
}
}
The fix was to initialize the b array with points to a, and then sort the b array in-place by comparing the corresponding values in the a array.
Simplifying the code
In your original code, the strategy was to have an array of pointers (b) that would point to the elements in a, and then get sorted. This was unnecessary here though, because characters are smaller than pointers, so letting b be an array of characters is more space-efficient and simpler.
Also, your spacing was very squished-together and somewhat difficult to read. Here's a solution that uses b as an array of characters instead of pointers, and offers improved spacing. Also, declaring the function above was not necessary. It suffices to define the function and declare it once.
#define CLASS_SIZE 10
#include <stdio.h>
void bubbleSortAWriteToB(const char a[], char b[]){
char temp;
int i,j;
// initialize b array to hold pointers to each element in a
for (i = 0; i < CLASS_SIZE; i++){
b[i] = a[i];
}
// in-place sort the b array
for(i = 0; i < CLASS_SIZE; i++){
for(j = i + 1; j < CLASS_SIZE - 1; j++){
if(b[j-1] > b[j]){
temp = b[j];
b[j] = b[j-1];
b[j-1] = temp;
}
}
}
}
int main(void){
int i;
// initialize array
char s_letters[CLASS_SIZE];
char letters[CLASS_SIZE] = {'a','r','p','b','r','c','x','e','w','j'};
// sort array
bubbleSortAWriteToB(letters, s_letters);
// print sorted array
int i;
for (i = 0; i < CLASS_SIZE; i++){
printf("%c\n", s_letters[i]);
}
return 0;
}
Solution 2
Your s_letters
is not properly initialized, yet you access it in:
*b[j] = a[j-1];
*b[j-1] = temp;
It's a segfault.
Solution 3
I compiled this with gcc -g
and ran it through Valgrind, and got this:
==54446== Non-existent physical address at address 0x100000000
==54446== at 0x100000EB0: bubbleSortAWriteToB (x.c:20)
==54446== by 0x100000DFE: main (x.c:9)
Line 20 is this:
*b[j] = a[j-1];
char *b[]
is an array of char
pointers, but you're trying to put something in the pointers without initializing them. If you really want to do this, you'd need to:
b[j] = malloc(sizeof(*b[j])); // Create some space for a char
*b[j] = a[j-1]; // Put the char in that space
But, I don't think that's what you actually want. If you just change it to char b[]
, and remove all of your *
's, it works fine.
Umut
Updated on July 07, 2022Comments
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Umut almost 2 years
I'm trying to bubble sort a character array in alphabetic order. My code is as follows:
#define CLASS_SIZE 10 #include <stdio.h> void bubbleSortAWriteToB(const char a[], char *b[]); int main(void){ char *s_letters[CLASS_SIZE]; char letters[CLASS_SIZE] = {'a','r','p','b','r','c','x','e','w','j'}; bubbleSortAWriteToB(letters,s_letters); return 0; } void bubbleSortAWriteToB(const char a[], char *b[]){ char temp; int i,j; for(i=0;i<CLASS_SIZE-1;i++){ for(j=1;j<CLASS_SIZE;j++){ if((int)a[j-1]>(int)a[j]){ temp = a[j]; *b[j] = a[j-1]; *b[j-1] = temp; } } } }
It doesn't give any kind of error but when i run it it gets stuck like it's kinda in a inifinte loop. But from what i can see it isn't that either. Can you help me out?
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Brendan Long over 12 yearsIt's not an infinite loop, it's a segmentation fault.
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Brendan Long over 12 yearsIt means that you're trying to access memory that you shouldn't be.
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Jonathan Grynspan over 12 yearsIt means it was a segmentation fault. ;) Is this homework?
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Michael Dorgan over 12 yearsYour second loop isn't setup properly for a bubble sort. It should be comparing against i somehow to reduce the work it does by half. Also, your swap is messed up. Use better var names to help yourself out a bit. a,b,i,j are hard for the human mind to parse. Fortran77 this is not.
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Brendan Long over 12 yearsYou may find this question useful: stackoverflow.com/questions/859634/…
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Adrian McCarthy over 12 yearsAren't these "find my bug" questions better suited to codereview.stackexchange.com? Interestingly, that's not one of the choices if you vote to close a question as "off topic". Perhaps "too localized" is appropriate, but migrating seems less harsh than outright closing.
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Yinda Yin over 12 years@AdrianMcCarthy: Code troubleshooting questions are specifically off-topic at CodeReview.SE. They want working code.
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Michael Dorgan over 12 yearsMaking those pointers means you didn't allocate a char array to place your stuff into, but an array of char *. Not nearly the same thing.
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Brendan Long over 12 years@UmutŞenaltan Read this question to see how to make a pointer to an array of char.
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Brendan Long over 12 years@UmutŞenaltan - My guess is that what you really want is just a
char*
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David Buck almost 4 yearsThis post has a comprehensive, accepted, answer with clear explanations that was posted 8 years ago. Whilst alternative answers are always welcome, their value (and their likelihood of receiving upvotes) will be much higher if you include an explanation of how your answer works and how it improves over existing answers, or what alternatives it offers.
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Gerhardh almost 4 yearsAlso noteworthy: The question is tagged with C language tag. Answers should provide solutions in the relevant programming language. Your code cannot be compiled with a C compiler.