C - error: storage size of ‘a’ isn’t known

Question

This is my C program...

#include <stdio.h>

struct xyx {
    int x;
    int y;
    char c;
    char str[20];
    int arr[2];
};

int main(void)
{
    struct xyz a;
    a.x = 100;
    printf("%d\n", a.x);
    return 0;
}

This is the error that I am getting....

Press ENTER or type command to continue

13structtest.c: In function ‘main’:
13structtest.c:13:13: error: storage size of ‘a’ isn’t known
13structtest.c:13:13: warning: unused variable ‘a’ [-Wunused-variable]

Solution 1

Your struct is called struct xyx but a is of type struct xyz. Once you fix that, the output is 100.

#include <stdio.h>

struct xyx {
    int x;
    int y;
    char c;
    char str[20];
    int arr[2];
};

int main(void)
{
    struct xyx a;
    a.x = 100;
    printf("%d\n", a.x);
    return 0;
}

Solution 2

To anyone with who is having this problem, its a typo error. Check your spelling of your struct delcerations and your struct

Solution 3

you define the struct as xyx but you're trying to create the struct called xyz.

Solution 4

correct typo of

struct xyz a;

to

struct xyx a;

Better you can try typedef, easy to b

Solution 5

Say it like this: struct xyx a;

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