C++ print value of a pointer
43,404
Solution 1
If it's really an array of (initialized) double pointers, i.e.:
double *arr[] = ...
// Initialize individual values
all you need is:
cout << *arr[i];
Solution 2
cout << *(arr[i]) will print the value.
Solution 3
cout << *(arr[i]);
Author by
user69514
Updated on March 21, 2020Comments
-
user69514 about 4 years
I have an array of double pointers, but every time I try do print one of the values the address gets printed. How do I print the actual value?
cout << arr[i] ? cout << &arr[i] ? they both print the address
Does anyone know?