Call and run php script from shell script

Question

I'm trying something simple yet can't figured it out. Trying to run one shell script which call php script from the site directory. My shell script is simple test.sh:

#!/bin/sh

LIST="/path/to/my/site/dir"
CONFIG="/usr/bin/php "

for i in $LIST
do
    . "${CONFIG}${i}/test.php"        
done

My test.php doesn't have errors and when I run it directly in browser it's working. It again simple script like

<?php
  // source code
?>

When I run ./test.sh result is

./test.sh: 8: .: Can't open /usr/bin/php /path/to/my/site/dir/test.php

Line 8 is . "${CONFIG}${i}/test.php"

I've tried also to add at the beginning of PHP file this line but the result is same

#!/usr/bin/php

UPDATE: Path to php

$ which -a php
/usr/bin/php

I've also made chmod +x test.php

Solution 1

The problem here is that you are quoting the entiore command you are trying to run as a single variable. As a result, you're not running php with foo.php as an argument but instead are attempting to execute a file called php foo.php. Here's a simpler example to show you what I mean:

$ var1="echo "
$ var2="foo"
$ set -x ## debugging info
$ "$var1$var2"
+ 'echo foo'      ### The shell tries to execute both vars as a single command
bash: echo foo: command not found

$ "$var1" "$var2"
+ 'echo ' foo     ### The shell tries to execute 'echo ' (echo with a space)
bash: echo foo: command not found  

So, the right way is to remove the space and quote each variable separately:

$ var1="echo"
$ var2="foo"
$ "$var1" "$var2"

If you do that though, you'll hit the next error. The . is the source command. That tries to read a shell script and execute it in the current session. You are giving it a php script instead. That won't work, you need to execute it, not source it.

Finally, always avoid using CAPITAL variable names. The shell's reserved variables are capitalized so it's a good idea to always use lower case variable names for your scripts.

Putting all this together (with a few other minor improvements), what you want is something like:

#!/bin/sh

list="/path/to/my/site/dir"
config="/usr/bin/php"

for i in "$list"
do
    "$config" "$i"/test.php
done

Solution 2

The problem in your code is the line:

. "${CONFIG}${i}/test.php"  

Remove the .

---

Here is another example:

$ ls -l

-rwxrwxr-x 1 bg bg 67 Oct 20 09:42 index.php
-rwxrwxr-x 1 bg bg 68 Oct 20 09:43 test.sh

index.php

<?php
    shell_exec('echo Hello > /tmp/hello.txt');
?>

test.sh

#!/bin/bash
/usr/bin/php index.php

Solution 3

Usually the command php is used for interpretation of PHP scripts in the shell.

$ php /path/script-name.php

I made simple test.sh and it works:

$ cat ./text.sh
#!/bin/bash
sudo php /var/www/wiki/maintenance/update.php

$ chmod +x ./test.sh
$ ./test.sh

It works.

After that I made complicated script as your example:

$ cat ./text.sh

#!/bin/sh

LIST=/var/www/wiki/maintenance
CONFIG=/usr/bin/php

for i in $LIST
do
    ${CONFIG} ${i}/update.php
done

$ sudo ./test.sh

It works!

$ cat ./text.sh

#!/bin/sh

LIST="/var/www/wiki/maintenance"
CONFIG="/usr/bin/php "

for i in $LIST
do
    ${CONFIG}${i}/update.php
done

$ sudo ./test.sh

Works also!

Comments

[Benny]

Try to append the -q, like this: /usr/bin/php -q /path/to/my/site/dir/test.php

[S.I.]

Thanks but same ./test.sh: 8: .: Can't open /usr/bin/php -q /path/to/my/site/dir/test.php

[Benny]

Ok, please try with the -f (Parse and execute file) like this: php -f test.php . make sure the file is executable chmod +x test.php

[S.I.]

When I run $ php /path/to/test.php directly in terminal it's working. But from shell script doesn't work

[pa4080]

Please remove the quote marks and the dot in line 8. Check the update of my answer.

[S.I.]

Without them I've got 1000+ lines in terminal with mysql/php configuration files..

[S.I.]

same ./test.sh: 8: .: Can't open php /path/to/my/site/dir/test.php

[S.I.]

When I run $ php /path/script-name.php directly in terminal it's working. But from shell script doesn't work

[pa4080]

Have you try run it as bash script #!/bin/bash?

[S.I.]

You mean #!/bin/bash php /path/to/test.php ?

[pa4080]

I mean to put it in the first line of the script instead of #!/bin/sh. This line indicates the shell who will interpret the script.

[S.I.]

Hm, different error now. Like the file isn't in the directory but it is ./test.sh: line 8: .: /usr/bin/php /path/to/my/site/dir/test.php: No such file or directory

[S.I.]

I've wrote full path there like /var/www/html/site/test.php

[S.I.]

Hm may be because of different users? -rwxrwxr-x 1 root root 382 Oct 20 09:46 test.sh and -rwxr-xr-x 1 root www-data 25 Aug 19 09:15 test.php ?

[pa4080]

However, #!/bin/sh isn't a problem. I think @Benny is right, remove ..

[S.I.]

with #!/bin/sh -> ./test.sh: line 8: /usr/bin/php /path/to/my/site/dir/test.php: not found

[Benny]

Make sure you set /path/to/my/site/dir/ to your real correct path

[S.I.]

I'm sure it's correct $ pwd -> /var/www/html/site

[S.I.]

Still I've got Not found and without quote marks I've got 1000+ lines in terminal with mysql/php configuration files.. Everything is same as your and Benny's examples and didn't work.

[S.I.]

When I run $ php /path/to/script/test.php directly in terminal it's work. But if I run same thing from shell script which contain same lines I've got not found. Even your first example #!/bin/bash sudo php /var/www/wiki/maintenance/update.php

[terdon]

Why are you using sudo? That just introduces a pointless security problem. Please only use sudo when you need it.

[S.I.]

Just for testing @SpasSpasov examples. Still doesn't want to execute php script from shell script. It's executed only if I run it directly in terminal

[terdon]

@S.I. yes, it won't. See my answer. You need to i) remove the extra space from CONFIG; ii) quote the variables separately and iii) execute it, not source it.

[S.I.]

Thank you very much for explaining and helped to get this script work!