Calling R script from python using rpy2

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source is a r function, which runs a r source file. Therefore in rpy2, we have two ways to call it, either:

import rpy2.robjects as robjects
r = robjects.r
r['source']('script.R')

or

import rpy2.robjects as robjects
r = robjects.r
r.source('script.R')

r[r.source("script.R")] is a wrong way to do it.

Same idea may apply to the next line.

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Efferalgan
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Efferalgan

Geomatics standardisation engineer at IGN France (National Institute of Geographic and Forestry Information). Huge Python fan, I code small projects when I'm bored.

Updated on November 22, 2020

Comments

  • Efferalgan
    Efferalgan over 3 years

    I'm very new to rpy2, as well as R.

    I basically have a R script, script.R, which contains functions, such as rfunc(folder). It is located in the same directory as my python script. I want to call it from Python, and then launch one of its functions. I do not need any output from this R function. I know it must be very basic, but I cannot find examples of R script-calling python codes. What I am currently doing, in Python:

    import rpy2.robjects as robjects
    
    def pyFunction(folder):
        #do python stuff 
        r=robjects.r
        r[r.source("script.R")]
        r["rfunc(folder)"]
        #do python stuff
    
    pyFunction(folder)
    

    I am getting an error on the line with source:

    r[r.source("script.R")] File "/usr/lib/python2.7/dist-packages/rpy2/robjects/__init__.py", line 226, in __getitem__ res = _globalenv.get(item) TypeError: argument 1 must be string, not ListVector

    I quite do not understand how the argument I give it is not a string, and I guess the same problem will then happen on the next line, with folder being a python string, and not a R thingie.

    So, how can I properly call my script?