Can I get the signature of a C# delegate by its type?

Question

Python question:

print(sum(range(5),-1)) 
from numpy import * 
print(sum(range(5),-1))

9
10

What is logical behind it? Thank you

Solution

    MethodInfo method = delegateType.GetMethod("Invoke");
    Console.WriteLine(method.ReturnType.Name + " (ret)");
    foreach (ParameterInfo param in method.GetParameters()) { 
        Console.WriteLine("{0} {1}", param.ParameterType.Name, param.Name);
    }

Comments

[Carcigenicate]

Numpy must be redefining range, and it has different boundry rules.

[jkr]

The first line is equivalent to 0+1+2+3+4+(-1). The third line is equivalent to 0+1+2+3+4 on axis=-1. Use import numpy as np and then rewrite the third line as np.sum(range(5),-1). And read the documentation for np.sum()

[jkr]

Numpy does not redefine range. The second argument in np.sum() is axis. It will only sum the items in the first argument.

[Carcigenicate]

Ahh, my bad. Shot in the dark. I didn't think a summing function could have different behavior.

[miradulo]

It's not so important, but sum doesn't add the start value at the end of the operation - it rather starts with the start value which defaults to 0, and adds the sequence to it. Like in CPython here.