Capture FFMPEG output
Solution 1
The problem is you catch only stdout and not stderr (see Standard Streams). Change this line:
$command = "/usr/bin/ffmpeg -i " . $src;
into
$command = "/usr/bin/ffmpeg -i " . $src . " 2>&1";
and give it another try :)
Solution 2
Use ffprobe instead, it's much quicker and supports JSON output.
$output = shell_exec('ffprobe -v quiet -print_format json -show_format -show_streams "path/to/yourfile.ext"');
$parsed = json_decode($output, true);
And you have all your video info in a php array! This is much faster than ffmpeg -i for some reason.
Solution 3
To get output status and output:
exec("ffmpeg -i input.avi output.mp4 2>&1", $output, $returnStatus);
print_r($output);
if($returnStatus === 0){
// success
}
else {
//fail
}
Andrew Ensley
With continuous experience beginning in 2004, I am a seasoned software developer, system administrator, database administrator, DevOps engineer, and team leader. My favorite areas of focus in development are performance, optimization, and security. I have experience with: Git, Java, C#, Python, TypeScript, Node.js, React.js, SQL, PHP, Linux, Windows, MacOS, Infrastructure-as-Code, Configuration-as-Code Azure, ADO, Jenkins, GitHub, Nexus RM/IQ, JFrog Artifactory, SonarQube, Docker, Kubernetes, Cloud Foundry, TAS, TKGi, DigitalOcean, Ansible, AWS Visual Studio Code, IntelliJ IDEA, Eclipse, PyCharm, Android Studio I love automation and open-source software.
Updated on June 04, 2022Comments
-
Andrew Ensley almost 2 years
I need to read the output from ffmpeg in order to even try the solution to my question from yesterday. This is a separate issue from my problem there, so I made a new question.
How the heck do I get the output from an
ffmpeg -i
command in PHP?This is what I've been trying:
<?PHP error_reporting(E_ALL); $src = "/var/videos/video1.wmv"; $command = "/usr/bin/ffmpeg -i " . $src; echo "<B>",$command,"</B><br/>"; $command = escapeshellcmd($command); echo "backtick:<br/><pre>"; `$command`; echo "</pre><br/>system:<br/><pre>"; echo system($command); echo "</pre><br/>shell_exec:<br/><pre>"; echo shell_exec($command); echo "</pre><br/>passthru:<br/><pre>"; passthru($command); echo "</pre><br/>exec:<br/><pre>"; $output = array(); exec($command,$output,$status); foreach($output AS $o) { echo $o , "<br/>"; } echo "</pre><br/>popen:<br/><pre>"; $handle = popen($command,'r'); echo fread($handle,1048576); pclose($handle); echo "</pre><br/>"; ?>
This is my output:
<B>/usr/bin/ffmpeg -i /var/videos/video1.wmv</B><br/> backtick:<br/> <pre></pre><br/> system:<br/> <pre></pre><br/> shell_exec:<br/> <pre></pre><br/> passthru:<br/> <pre></pre><br/> exec:<br/> <pre></pre><br/> popen:<br/> <pre></pre><br/>
I don't get it.
safe_mode
is off. There's nothing indisable_functions
. The directory is owned bywww-data
(the apache user on my Ubuntu system). I get a valid status back fromexec()
andsystem()
and running the same command from the command line give me tons of output. I feel like I must be missing something obvious but I have no idea what it is. -
Andrew Ensley almost 15 yearsAhhh... yeah. That makes sense because my return status is 1 (not 0). I wish that worked, but I still get the same result, just with: "<B>/usr/bin/ffmpeg -i /var/videos/video1.wmv 2>&1</B>" at the beginning. I'll do some research to see if Ubuntu has some differences for redirecting stderr.
-
Werner almost 15 yearsI can confirm that the following should work. I've used this exact line in a hobby project once. exec('ffmpeg -i ' . escapeshellarg($filepath) . ' 2>&1', $output);
-
Andrew Ensley almost 15 yearsAhha! I figured it out. My problem was the escapeshellcmd() function. It was changing "2>&1" to "2\>\&1". I tried your code and it worked. Lesson I've learned: output the command after you've made all modifications to it =p. Thanks.
-
Andrew Ensley over 11 yearsWow, what a useful function! I had no idea this existed. Thank you!
-
tweak2 over 11 yearsIt is also much quicker than initializing ffmpeg every time!
-
Farzad almost 7 yearsniiiiiiiiiiiiceeeeeeeeeeeee