Check whether a path exists on a remote host using paramiko

23,487

Solution 1

See the errno module for constants defining all those error codes. Also, it's a bit clearer to use the errno attribute of the exception than the expansion of the __init__ args, so I'd do this:

except IOError, e: # or "as" if you're using Python 3.0
  if e.errno == errno.ENOENT:
    ...

Solution 2

Paramiko literally raises FileNotFoundError

def sftp_exists(sftp, path):
    try:
        sftp.stat(path)
        return True
    except FileNotFoundError:
        return False

Solution 3

There is no "exists" method defined for SFTP (not just paramiko), so your method is fine.

I think checking the errno is a little cleaner:

def rexists(sftp, path):
    """os.path.exists for paramiko's SCP object
    """
    try:
        sftp.stat(path)
    except IOError, e:
        if e[0] == 2:
            return False
        raise
    else:
        return True
Share:
23,487
Sridhar Ratnakumar
Author by

Sridhar Ratnakumar

Updated on July 09, 2022

Comments

  • Sridhar Ratnakumar
    Sridhar Ratnakumar almost 2 years

    Paramiko's SFTPClient apparently does not have an exists method. This is my current implementation:

    def rexists(sftp, path):
        """os.path.exists for paramiko's SCP object
        """
        try:
            sftp.stat(path)
        except IOError, e:
            if 'No such file' in str(e):
                return False
            raise
        else:
            return True
    

    Is there a better way to do this? Checking for substring in Exception messages is pretty ugly and can be unreliable.