CIDR notation and IP range validator pattern
14,156
Pattern pattern = Pattern.compile("^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])(\\/(\\d|[1-2]\\d|3[0-2]))?$");
Matcher matcher = pattern.matcher("84.240.40.0/24");
if (matcher.find()) {
System.out.println(matcher.group());
}
Output:
84.240.40.0/24
this pattern matches IPv4 address and IPv4 CIDR range if you want tomatch only range ,you should remove last question mark
Author by
Maverick
Updated on June 16, 2022Comments
-
Maverick almost 2 years
I have a pattern to validate normal IP addresses, that is :
private static final String PATTERN = "^([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." + "([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." + "([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." + "([01]?\\d\\d?|2[0-4]\\d|25[0-5])$";
And a validate method to check if the input is a valid IP address or not :
private static boolean validate(final String ip){ Pattern pattern = Pattern.compile(PATTERN); Matcher matcher = pattern.matcher(ip); return matcher.matches(); }
But, now I need to add validation for CIDR (e.g. 84.240.40.0/24) notation and IP-range without host (e.g. 172.24.105), I tried many different patterns but not getting something concrete. Any suggestions?