Classpath resource within jar
Solution 1
Use getResource
instead of getSystemResource
to use a resource specific to a given classloader instead of the system. For example, try any of the following:
URL resource = getClass().getClassLoader().getResource("R.txt");
URL resource = Foo.class.getClassLoader().getResource("R.txt");
URL resource = getClass().getResource("/R.txt");
URL resource = Foo.class.getResource("/R.txt");
Note the leading slash when calling Class.getResource
instead of ClassLoader.getResource
; Class.getResource
is relative to the package containing the class unless you have a leading slash, whereas ClassLoader.getResource
is always absolute.
Solution 2
Apparently your JAR is not loaded by the system classloader, so getSystemResource()
can't work. This should work:
ClassFromProjectA.class.getClassLoader().getResource("R.txt")
IMO more convenient is putting resources inside the same package as the classes that use them, so you can use the shorter
ClassFromProjectA.class.getResource("R.txt")
(or, inside that class just getClass().getResource("R.txt")
)
Solution 3
Does ClassLoader.getResource() work ? At the moment you're simply specifying that the system classloader is to be used.
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Johan Sjöberg
Updated on July 09, 2022Comments
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Johan Sjöberg almost 2 years
I have a project A, which contains some java files and a classpath resource R.txt. Within the project I use ClassLoader.getSystemResource("R.txt"); to retrieve R.txt.
Then I have a project B which includes project A's jar-file. Now getSystemResource("R.txt") wont find the textfile (and yes, it's still in the root of the jar file). Even trying "/R.txt" as was suggested on some other site didn't work. Any ideas?
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Johan Sjöberg over 14 yearsAmazing. This completely solved my problem. Thanks for the superfast input // Johan
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Johan Sjöberg over 14 yearsWorks like a charm. Just had to use the correct classloader :)
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Ensom Hodder over 11 yearsOne more related question: we may get InputStream from this URL resources, but how could we create a File object from the returned URL object. I tried to create a URI object with the "URLObject.toURI()", and use this URI object to create a file, unfortunately, it throws an "URI is not hierarchical exception". Could you give me some help ? Thanks a lot .
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Jon Skeet over 11 years@EnsomHodder: Um, not sure - but not all resources are files - in particular, it won't be if it's in a jar file.
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asgs over 11 yearsThanks for the explanation of when the
/
is needed. -
Jon Skeet about 10 years@Jeff: I've rolled back the edit because
Class.ClassLoader
isn't a classname. The method is in theClassLoader
class. Yes, you often callClass.getClassLoader()
to get a classloader, but the call is stillClassLoader.getResource
...