CLLocation Category for Calculating Bearing w/ Haversine function

11,850

Solution 1

Your code seems fine to me. Nothing wrong with the calculous. You don't specify how far off your results are, but you might try tweaking your radian/degrees converters to this:

double DegreesToRadians(double degrees) {return degrees * M_PI / 180.0;};
double RadiansToDegrees(double radians) {return radians * 180.0/M_PI;};

If you are getting negative bearings, add 2*M_PI to the final result in radiansBearing (or 360 if you do it after converting to degrees). atan2 returns the result in the range -M_PI to M_PI (-180 to 180 degrees), so you might want to convert it to compass bearings, using something like the following code

if(radiansBearing < 0.0)
    radiansBearing += 2*M_PI;

Solution 2

This is a porting in Swift of the Category at the beginning:

import Foundation
import CoreLocation
public extension CLLocation{

    func DegreesToRadians(_ degrees: Double ) -> Double {
        return degrees * M_PI / 180
    }

    func RadiansToDegrees(_ radians: Double) -> Double {
        return radians * 180 / M_PI
    }


    func bearingToLocationRadian(_ destinationLocation:CLLocation) -> Double {

        let lat1 = DegreesToRadians(self.coordinate.latitude)
        let lon1 = DegreesToRadians(self.coordinate.longitude)

        let lat2 = DegreesToRadians(destinationLocation.coordinate.latitude);
        let lon2 = DegreesToRadians(destinationLocation.coordinate.longitude);

        let dLon = lon2 - lon1

        let y = sin(dLon) * cos(lat2);
        let x = cos(lat1) * sin(lat2) - sin(lat1) * cos(lat2) * cos(dLon);
        let radiansBearing = atan2(y, x)

        return radiansBearing
    }

    func bearingToLocationDegrees(destinationLocation:CLLocation) -> Double{
        return   RadiansToDegrees(bearingToLocationRadian(destinationLocation))
    }
}

Solution 3

Here is another implementation

public func bearingBetweenTwoPoints(#lat1 : Double, #lon1 : Double, #lat2 : Double, #lon2: Double) -> Double {

func DegreesToRadians (value:Double) -> Double {
    return value * M_PI / 180.0
}

func RadiansToDegrees (value:Double) -> Double {
    return value * 180.0 / M_PI
}

let y = sin(lon2-lon1) * cos(lat2)
let x = (cos(lat1) * sin(lat2)) - (sin(lat1) * cos(lat2) * cos(lat2-lon1))

let degrees = RadiansToDegrees(atan2(y,x))

let ret = (degrees + 360) % 360

return ret;

}

Solution 4

This is an another CLLocation extension can be used in Swift 3 and Swift 4

public extension CLLocation {

    func degreesToRadians(degrees: Double) -> Double {
        return degrees * .pi / 180.0
    }

    func radiansToDegrees(radians: Double) -> Double {
        return radians * 180.0 / .pi
    }

    func getBearingBetweenTwoPoints(point1: CLLocation, point2: CLLocation) -> Double {
        let lat1 = degreesToRadians(degrees: point1.coordinate.latitude)
        let lon1 = degreesToRadians(degrees: point1.coordinate.longitude)

        let lat2 = degreesToRadians(degrees: point2.coordinate.latitude)
        let lon2 = degreesToRadians(degrees: point2.coordinate.longitude)

        let dLon = lon2 - lon1

        let y = sin(dLon) * cos(lat2)
        let x = cos(lat1) * sin(lat2) - sin(lat1) * cos(lat2) * cos(dLon)
        let radiansBearing = atan2(y, x)

        return radiansToDegrees(radians: radiansBearing)
    }

}

Solution 5

Working Swift 3 and 4

Tried so many versions and this one finally gives correct values!

extension CLLocation {


    func getRadiansFrom(degrees: Double ) -> Double {

        return degrees * .pi / 180

    }

    func getDegreesFrom(radians: Double) -> Double {

        return radians * 180 / .pi

    }


    func bearingRadianTo(location: CLLocation) -> Double {

        let lat1 = self.getRadiansFrom(degrees: self.coordinate.latitude)
        let lon1 = self.getRadiansFrom(degrees: self.coordinate.longitude)

        let lat2 = self.getRadiansFrom(degrees: location.coordinate.latitude)
        let lon2 = self.getRadiansFrom(degrees: location.coordinate.longitude)

        let dLon = lon2 - lon1

        let y = sin(dLon) * cos(lat2)
        let x = cos(lat1) * sin(lat2) - sin(lat1) * cos(lat2) * cos(dLon)

        var radiansBearing = atan2(y, x)

        if radiansBearing < 0.0 {

            radiansBearing += 2 * .pi

        }


        return radiansBearing
    }

    func bearingDegreesTo(location: CLLocation) -> Double {

        return self.getDegreesFrom(radians: self.bearingRadianTo(location: location))

    }


}

Usage:

let degrees = location1.bearingDegreesTo(location: location2)
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11,850
Nick
Author by

Nick

Updated on June 23, 2022

Comments

  • Nick
    Nick about 2 years

    I'm trying to write a category for CLLocation to return the bearing to another CLLocation.

    I believe I'm doing something wrong with the formula (calculous is not my strong suit). The returned bearing is always off.

    I've been looking at this question and tried applying the changes that were accepted as a correct answer and the webpage it references:

    Calculating bearing between two CLLocationCoordinate2Ds

    http://www.movable-type.co.uk/scripts/latlong.html

    Thanks for any pointers. I've tried incorporating the feedback from that other question and I'm still just not getting something.

    Thanks

    Here's my category -

    ----- CLLocation+Bearing.h

    #import <Foundation/Foundation.h>
    #import <CoreLocation/CoreLocation.h>
    
    
    @interface CLLocation (Bearing)
    
    -(double) bearingToLocation:(CLLocation *) destinationLocation;
    -(NSString *) compassOrdinalToLocation:(CLLocation *) nwEndPoint;
    
    @end
    

    ---------CLLocation+Bearing.m

    #import "CLLocation+Bearing.h"
    
    double DegreesToRadians(double degrees) {return degrees * M_PI / 180;};
    double RadiansToDegrees(double radians) {return radians * 180/M_PI;};
    
    
    @implementation CLLocation (Bearing)
    
    -(double) bearingToLocation:(CLLocation *) destinationLocation {
    
     double lat1 = DegreesToRadians(self.coordinate.latitude);
     double lon1 = DegreesToRadians(self.coordinate.longitude);
    
     double lat2 = DegreesToRadians(destinationLocation.coordinate.latitude);
     double lon2 = DegreesToRadians(destinationLocation.coordinate.longitude);
    
     double dLon = lon2 - lon1;
    
     double y = sin(dLon) * cos(lat2);
     double x = cos(lat1) * sin(lat2) - sin(lat1) * cos(lat2) * cos(dLon);
     double radiansBearing = atan2(y, x);
    
     return RadiansToDegrees(radiansBearing);
    }
    
    • Kyle Redfearn
      Kyle Redfearn almost 10 years
      Why are you converting the lat and lon values from degrees to radians? Does the Haversine function require that conversion?
    • Kyle Redfearn
      Kyle Redfearn almost 10 years
      To answer my own question, Yes. The Haversine function reqqires that conversion as shown here: movable-type.co.uk/scripts/latlong.html
  • Nick
    Nick over 13 years
    Thank you so much! I should have given some expected and actual results but you spotted the issue anyway. I was just not handling the negative degrees and converting to compass degrees. Good point specifying the 180's as floats as well. Everything working perfectly now.
  • Fabrizio Bartolomucci
    Fabrizio Bartolomucci almost 9 years
    I do not understand it these algorithms how may sin be applied to a coordinate in degrees rather than in radians.
  • Jeef
    Jeef almost 9 years
    williams.best.vwh.net/avform.htm#Crs its the way its done in aviation i believe.
  • Fabrizio Bartolomucci
    Fabrizio Bartolomucci almost 9 years
    My problem is that whatever algorithm I choose gives a different result. At the bottom a Swift porting of the afore written category.
  • Fabrizio Bartolomucci
    Fabrizio Bartolomucci almost 9 years
    And in fact it first translate the degrees to radians. Yet I am in the black how even taking directly the degrees gives similar results.
  • Jeef
    Jeef almost 9 years
    Every single algorithm is going to give you a different result - due to the different nature of trying to do linear geometry on an elipsoid. All these algorithms are just approximations and use different projections. Cosine correction is good for small distances to do an xy approximation etc. But other algorithms are better for different distances.
  • Adrian
    Adrian about 2 years
    I tried this out and I'm "in the neighborhood", but the degrees are off by like 3 or 4, which is pretty hefty. I think the math on this might be off a bit.