Command line arguments, reading a file

110,783

Solution 1

You can use int main(int argc, char **argv) as your main function.

argc - will be the count of input arguments to your program.
argv - will be a pointer to all the input arguments.

So, if you entered C:\myprogram myfile.txt to run your program:

  • argc will be 2
  • argv[0] will be myprogram.
  • argv[1] will be myfile.txt.

More details can be found here

To read the file:
FILE *f = fopen(argv[1], "r"); // "r" for read

For opening the file in other modes, read this.

Solution 2

  1. Declare your main like this

    int main(int argc, char* argv [])

    • argc specified the number of arguments (if no arguments are passed it's equal to 1 for the name of the program)

    • argv is a pointer to an array of strings (containing at least one member - the name of the program)

    • you would read the file from the command line like so: C:\my_program input_file.txt

  2. Set up a file handle:

    File* file_handle;

  3. Open the file_handle for reading:

    file_handle = fopen(argv[1], "r");

    • fopen returns a pointer to a file or NULL if the file doesn't exist. argv1, contains the file you want to read as an argument

    • "r" means that you open the file for reading (more on the other modes here)

  4. Read the contents using for example fgets:

    fgets (buffer_to_store_data_in , 50 , file_handle);

    • you need a char * buffer to store the data in (such as an array of chars), the second argument specifies how much to read and the third is a pointer to a file
  5. Finally close the handle

    fclose(file_handle);

All done :)

Solution 3

This is the Programming 101 way. It takes a lot for granted, and it doesn't do any error-checking at all! But it will get you started.

/* this has declarations for fopen(), printf(), etc. */
#include <stdio.h>

/* Arbitrary, just to set the size of the buffer (see below).
   Can be bigger or smaller */
#define BUFSIZE 1000

int main(int argc, char *argv[])
{
    /* the first command-line parameter is in argv[1] 
       (arg[0] is the name of the program) */
    FILE *fp = fopen(argv[1], "r"); /* "r" = open for reading */

    char buff[BUFSIZE]; /* a buffer to hold what you read in */

    /* read in one line, up to BUFSIZE-1 in length */
    while(fgets(buff, BUFSIZE - 1, fp) != NULL) 
    {
        /* buff has one line of the file, do with it what you will... */

        printf ("%s\n", buff); /* ...such as show it on the screen */
    }
    fclose(fp);  /* close the file */ 
}
Share:
110,783
user2440329
Author by

user2440329

Updated on March 20, 2020

Comments

  • user2440329
    user2440329 over 4 years

    If i entered into the command line C: myprogram myfile.txt

    How can I use myfile in my program. Do I have to scanf it in or is there an arbitrary way of accessing it.

    My question is how can I use the myfile.txt in my program.

    int
    main(){
        /* So in this area how do I access the myfile.txt 
        to then be able to read from it./*