Comparing string and boolean in Expression language

11,513

Solution 1

This is the behaviour of the language as defined in the EL specification:

A {==,!=,eq,ne} B

  • other rules elided
  • If A or B is Boolean coerce both A and B to Boolean, apply operator

Coerce A to Boolean

  • If A is null or "", return false
  • Otherwise, if A is a Boolean, return A
  • Otherwise, if A is a String, and Boolean.valueOf(A) does not throw an exception, return it
  • Otherwise, error

So, the string literal is coerced to a boolean via Boolean.valueOf("error") which returns false.

Solution 2

If one of the both sides in EL is a Boolean (or boolean) and the other side is a String, then the String will be parsed to Boolean by Boolean#valueOf() whose javadoc says the following:

Returns a Boolean with a value represented by the specified string. The Boolean returned represents a true value if the string argument is not null and is equal, ignoring case, to the string "true".

So, it returns false and this is indeed equal to false.

You need to rewrite your EL expression to take into account that the type can be both a boolean and a string, or just to stick to a single type and not to mix types in a single attribute.

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Paolo
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Paolo

Updated on June 12, 2022

Comments

  • Paolo
    Paolo almost 2 years

    I have this behaviour I do not really understand

    ${someVar}
    ${someVar.class.name}      
    ${someVar == 'error'}
    

    outputs

    false
    java.lang.Boolean
    true
    
    1. How can it be exlpained?
    2. What it the correct way to write the test in order to first test if the two 'things' have the same type and then if their value is the same?