conditional binary operator expected

Question

I want to modify reset password link. I dont want to modify vendor file.

For example: I receive link from email: http://localhost:8000/password/reset?51e5bd40dab074e8975100a2e84c08f457ec54c4cf6e0349fbe07ff67978793f

Needs to be change: http://localhost:8000/password/reset?token=51e5bd40dab074e8975100a2e84c08f457ec54c4cf6e0349fbe07ff67978793f&[email protected]

How it is possible?

Thanks in advance

Solution

1. You're missing $ in front of var when you call it, like you wrote it, it will be literally var.
2. Consider possible vulnerabilities of your script when using [[ ... ]] or (( ... )) together with variables you cannot control. In your case, it might be better to use [ "$var" -ne 0 ].
3. You're missing a space between != and 0 (this is the source of the error!)
4. != is a string comparison operator, while it might work in your example, you want to use -ne to compare integers.

Make use of shellcheck.

Comments

[Stéphane Chazelas]

Note that (( var !=0 )) would also work here, but like [[ "$var" -ne 0 ]] would be an arbitrary command injection vulnerability if the nature of the output of the command being captured is not under your control.

[Stéphane Chazelas]

In [[ $var -ne 0 ]] (with or without the quotes, the quotes being not necessary in this particular case) or (( var!=0 )), the contents of $var is evaluated as an arithmetic expressions and bad things can happen then. [ "$var" -ne 0 ] (the quotes being necessary here as [ is an ordinary command) is safe in bash (but not all other shells), as $var is interpreted as a decimal integer only. [ "$var" != 0 ] (or the [[ $var != 0 ]] kshism) is safe as well but would return true if $var contains 00 as it's a string comparison.