Convert an Integer into 32bit Binary Python

Question

I am trying to make a program that converts a given integer(limited by the value 32 bit int can hold) into 32 bit binary number. For example 1 should return (000..31times)1. I have been searching the documents and everything but haven't been able to find some concrete way. I got it working where number of bits are according to the number size but in String. Can anybody tell a more efficient way to go about this?

Solution 1

'{:032b}'.format(n) where n is an integer. If the binary representation is greater than 32 digits it will expand as necessary:

>>> '{:032b}'.format(100)
'00000000000000000000000001100100'
>>> '{:032b}'.format(8589934591)
'111111111111111111111111111111111'
>>> '{:032b}'.format(8589934591 + 1)
'1000000000000000000000000000000000'    # N.B. this is 33 digits long

Solution 2

You can just left or right shift integer and convert it to string for display if you need.

>>> 1<<1
2
>>> "{:032b}".format(2)
'00000000000000000000000000000010'
>>>

or if you just need a binary you can consider bin

>>> bin(4)
'0b100'

Comments

[Josh Kelley]

Possible duplicate of python convert to binary and keep leading zeros

[Pooja Gupta]

But this returns a string,I need a binary number because I want to add features like left shift and right shift also.

[juanpa.arrivillaga]

@PoojaGupta You are looking for an int

[Scott]

How about converting negative values?