Convert dateTime to unix epoch in xslt

13,599

Solution 1

This transformation:

<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema">
    <xsl:output method="text"/>

 <xsl:template match="/">
   <xsl:sequence select="current-dateTime()"/>

   <xsl:sequence select=
   "( current-dateTime() - xs:dateTime('1970-01-01T00:00:00') )
    div
     xs:dayTimeDuration('PT1S')
     "/>
 </xsl:template>
</xsl:stylesheet>

when applied on any XML document (not used), produces the wanted result -- the current date-time and its Unix epoch (the number of seconds since 1/1/1970 ):

2010-08-12T06:26:54.273-07:00    1281594414.273

Solution 2

A pure xsl 1.0 lib example:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:date="https://github.com/ilyakharlamov/pure-xsl/date"
    version="1.0">
    <xsl:import href="https://raw.github.com/ilyakharlamov/pure-xsl/master/date.xsl"/>
    <xsl:template match="/">
        <xsl:variable name="time_as_timestamp" select="1365599995640"/>
        <xsl:text>time_as_timestamp:</xsl:text><xsl:value-of select="$time_as_timestamp"/><xsl:text>&#x0A;</xsl:text>
        <xsl:variable name="time_as_xsdatetime">
            <xsl:call-template name="date:date-time">
                <xsl:with-param name="timestamp" select="$time_as_timestamp"/>
            </xsl:call-template>
        </xsl:variable>
        <xsl:text>time_as_xsdatetime:</xsl:text><xsl:value-of select="$time_as_xsdatetime"/><xsl:text>&#x0A;</xsl:text>
        <xsl:text>converted back:</xsl:text>
        <xsl:call-template name="date:timestamp">
            <xsl:with-param name="date-time" select="$time_as_xsdatetime"/>
        </xsl:call-template>
    </xsl:template>
</xsl:stylesheet>

Output:

time_as_timestamp:1365599995640
time_as_xsdatetime:2013-04-10T13:19:55.640Z
converted back:1365599995640

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Anna
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Anna

Updated on April 17, 2020

Comments

  • Anna
    Anna about 4 years

    I have a dateTime variable, and I want to convert it to a decimal value of epoch. How can this be done?

    I tried using:

    seconds-from-duration($time, xs:dateTime('1970-01-01T00:00:00'))
    

    but it just returns 0.

    Please advice. Thanks.

  • Admin
    Admin almost 14 years
    +1 for divide by xs:duration (I was extracting each component, so I've deleted the answer). But I keep thinking if time zone is defined for *nix epoch.
  • aendra
    aendra over 8 years
    Considering that LibXML2 still doesn't support XPath 2.0 functions — in 20-freaking-15 — this answer is awesome and totally saved me a boatload of time. Thanks!