Converting a string into an int array

Question

While programming in C I got stuck at the following code-snippet:

While converting from char array input to integer array digit, only the ANSI code is converted to the digit array.

How can I make sure the correct integer-value is given to this array ?

This is the relevant code:

int main(void) {
    int x = 0;
    int y = 0 
    char input[12] = {0};
    int digit[12] = {0};

    scanf("%s", &input[0]);
    fflush(stdin);

    while (input[y] != '\0') {
        if (isdigit(input[y])) {
            digit[x++] = input[y++];
            count++;
        }
        else y++;
    }
}

Solution 1

scanf("%s", &string[0]);  

read into input character array. you are reading into some other variable.

scanf("%s",input);

or even best

fgets(input,sizeof input, stdin );

---

  digit[x++] = input[y++]-'0';   
   // substract `'0'` from your character and assign to digit array.

For example if input[i]=='3' ==> '3'-'0' will result in integer digit 3

Solution 2

I would suggest you to use strtol or sscanf in a loop. That would make things easier for you.

Something like this:

char *c = "12 23 45 9";
int i[5];
sscanf(inputstring, "%d %d %d %d %d", &i[0], &i[1], &i[2], &i[3], &i[4]);

Sample example using atoi() which another option:

int main(int argc,char *argv[]){
    char y[10] = "0123456789";
    char x[3];
    int i;

    x[0] = y[8];
    x[1] = y[9];
    x[2] = '\0';

    i=atoi(x);
}