Converting Hex to RGB value in Python

Question

Working off Jeremy's response here: Converting hex color to RGB and vice-versa I was able to get a python program to convert preset colour hex codes (example #B4FBB8), however from an end-user perspective we can't ask people to edit code & run from there. How can one prompt the user to enter a hex value and then have it spit out a RGB value from there?

Here's the code I have thus far:

def hex_to_rgb(value):
    value = value.lstrip('#')
    lv = len(value)
    return tuple(int(value[i:i + lv // 3], 16) for i in range(0, lv, lv // 3))


def rgb_to_hex(rgb):
    return '#%02x%02x%02x' % rgb

hex_to_rgb("#ffffff")              # ==> (255, 255, 255)
hex_to_rgb("#ffffffffffff")        # ==> (65535, 65535, 65535)
rgb_to_hex((255, 255, 255))        # ==> '#ffffff'
rgb_to_hex((65535, 65535, 65535))  # ==> '#ffffffffffff'

print('Please enter your colour hex')

hex == input("")

print('Calculating...')
print(hex_to_rgb(hex()))

Using the line print(hex_to_rgb('#B4FBB8')) I'm able to get it to spit out the correct RGB value which is (180, 251, 184)

It's probably super simple - I'm still pretty rough with Python.

Solution 1

I believe that this does what you are looking for:

h = input('Enter hex: ').lstrip('#')
print('RGB =', tuple(int(h[i:i+2], 16) for i in (0, 2, 4)))

(The above was written for Python 3)

Sample run:

Enter hex: #B4FBB8
RGB = (180, 251, 184)

Writing to a file

To write to a file with handle fhandle while preserving the formatting:

fhandle.write('RGB = {}'.format( tuple(int(h[i:i+2], 16) for i in (0, 2, 4)) ))

Solution 2

You can use ImageColor from Pillow.

>>> from PIL import ImageColor
>>> ImageColor.getcolor("#23a9dd", "RGB")
(35, 169, 221)

Solution 3

Just another option: matplotlib.colors module.

Quite simple:

>>> import matplotlib.colors
>>> matplotlib.colors.to_rgb('#B4FBB8')
(0.7058823529411765, 0.984313725490196, 0.7215686274509804)

Note that the input of to_rgb need not to be hexadecimal color format, it admits several color formats.

You can also use the deprecated hex2color

>>> matplotlib.colors.hex2color('#B4FBB8')
(0.7058823529411765, 0.984313725490196, 0.7215686274509804)

The bonus is that we have the inverse function, to_hex and few extra functions such as, rgb_to_hsv.

Solution 4

A lazy option: webcolors package has a hex_to_rgb function.

Solution 5

PIL also has this function, in ImageColor.

from PIL import ImageColor

ImageColor.getrgb("#9b9b9b")

And if you want the numbers from 0 to 1

[i/256 for i in ImageColor.getrgb("#9b9b9b")]

View more solutions

Comments

[User]

possible duplicate: stackoverflow.com/questions/5661725/…

[koukouviou]

It is better to avoid overriding hex. Maybe something like hex_in or similar is better

[Julian White]

Good point, @koukouviou - Python reports it as built-in name.

[Julian White]

Beautiful. Cuts 23 lines down to two, only suggestion is fixing to for i in (0, 2, 4)))

[Julian White]

Question, John1024, I'm writing the result (example #FFFFFF being (255, 255, 255)) to a file using f.write, it requests it be a string rather than a tuple. Is there any way I can convert it to a string preserving the commas and spaces? Cheers :)

[John1024]

@JulianWhite No problem. I updated the answer using string formatting suitable for f.write.

[Gürol Canbek]

By the way, currently webcolors does not have a hex_to_rgb where the tuples are specified in decimal value in range 0 and 1 (say hex_to_rgb_decimal). But, you can use this code that imports numpy and webcolors: tuple(numpy.array(webcolors.hex_to_rgb('#9C0006'))/255.0)

[Typewar]

This was apparently the only solution that worked for me.

[Typewar]

Getting error "TypeError: 'float' object cannot be interpreted as an integer"

[John1024]

@Typewar Are you using python3? (This code would have to be modified if you needed to use it with the soon-to-be-obsolete python2.) What exactly did you enter in response to the prompt? What is the full and complete error message that you see?

[bugmenot123]

Well the question was about hex.

[MathanKumar]

Hey @SuperNova how to get the name of color instead of pixel values?

[SuperNova]

hwy @Mvk1312. Please check this. stackoverflow.com/questions/9694165/…

[Ideogram]

It does not answer the question, but it gives insight into how it's done conceptually, so +1. (teach a man how to fish and so on... )

[Ideogram]

In case you need values from 0…1: rgb = [i/256 for i in (ImageColor.getrgb("#9b9b9b"))]

[ilykos]

I believe the last comment to be wrong. 255/256=0.99609. The values returned from ImageColor.getrbb are [0 ... 255], hard bounded by 255 upper limit. By dividing 256 you will never reach 1.0. Unless I am very wrong here, I suggest you change this to i/255.

[WinEunuuchs2Unix]

Although implied it doesn't, this works in Python 2.7.12 as well. Just remember to .lstrip('#') the tkinter color coded being passed to your function.

[John1024]

@WinEunuuchs2Unix I get your point but to obtain the same screen output from py2, one should either change the print command to print 'RGB =', tuple(int(h[i:i+2], 16) for i in (0, 2, 4)) or else precede the print command with from __future__ import print_function

[WinEunuuchs2Unix]

@John1024 Gotcha. When I started out with 2.7.12 I was using print from the future I forgot all about that problem for others.

[Barış Şenyerli]

I found this solution is fastest one.